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Pavlova-9 [17]
3 years ago
7

Prove csc(pi/2 -x) = sec x

Mathematics
1 answer:
kifflom [539]3 years ago
6 0

Answer:

see explanation

Step-by-step explanation:

Consider the left side

Using the trigonometric identities

csc x = \frac{1}{sinx} and sec x = \frac{1}{cosx}

Note that sin( \frac{\pi }{2} - x) = cos x

Hence

csc(\frac{\pi }{2} - x)

= \frac{1}{sin(\frac{\pi }{2}-x) }

= \frac{1}{cosx}

= sec x = right side ⇒ proven

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64

Step-by-step explanation:

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3 years ago
If both the numerator and denominator of 48/64 are divided by 8, the fraction will be in lowest terms. True False
Licemer1 [7]
If 48/64 are both divided by 8 you would get 6/8! these can still be reduced to 3/4, So FALSE!
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4.44 x 4 = please my sister needs it
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17.76

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6 0
3 years ago
Square lMNO is shown in the diagram below what are the coordinates of the midpoint of a diagonal LN
sashaice [31]

Answer:

The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

answer (4)

Step-by-step explanation:

* Lets explain how to find the midpoint of a line

- The coordinates of the midpoint of a line whose endpoints are (x1 , y1)

 and (x2 , y2) are x=\frac{x_{1}+x_{2}}{2},y=\frac{y_{1}+y_{2}}{2}

∵ LMNO is a square

∵ The coordinates of point L are (-6 , 1)

∵ The coordinates of point N are (1 , 8)

- Let the coordinates of point L are (x1 , y1) , the coordinates of point

 N are (x2 , y2) and the coordinates of the midpoint of LN are (x , y)

∴ x1 = -6 , x2 = 1 and y1 = 1 , y2 = 8

- Use the rule of the midpoint above to find the midpoint (x , y)

∵ x=\frac{-6+1}{2}=\frac{-5}{2}=-2\frac{1}{2}

∵ y=\frac{1+8}{2}=\frac{9}{4}=4\frac{1}{2}

∴ The coordinates of the midpoint are (-2\frac{1}{2},4\frac{1}{2})

* The coordinates of the midpoint of LN are (-2\frac{1}{2},4\frac{1}{2})

8 0
3 years ago
Find x and y. <br>x - y = 2 <br>3x - y = 12​
omeli [17]

the answer is

X=5

y=3

hope you like it

8 0
1 year ago
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