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11Alexandr11 [23.1K]
3 years ago
14

John conducted an experiment to test whether heat had an effect on a certain type of bacteria. He collected approximately 800 sp

ecimens of bacteria. After exposing them to 100º heat, John noticed that the bacteria colony was losing half of its population every hour. Complete the chart below to show how much bacteria was left each hour, then graph.
# of hours Process # of bacteria
0
1
2
3
4
5
Equation
Mathematics
1 answer:
prohojiy [21]3 years ago
6 0

Answer:

0 800

1 400

2 200

3 100

4 50

5 25

Equation

I am not all the way sure and don't want to Guide you in the wrong direction, so I am going to let someone else answer. The chart should be right though.

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Find the indicated length. find LM
Roman55 [17]

The overall length is given as 22.

The line is split into 2 parts X and 3X.

So we have X + 3X = 22

Add X and #X to get 4X:

4X = 22

Divide both sides by 4 to get X:

X = 22 /4

X = 5.5

Now we know what X is so now replace x with 5.5 and solve for LM:

LM = 3X = 3*5.5 = 16.5

7 0
3 years ago
What's the answer and how to get it
Murrr4er [49]
The answer is B.)
The answers are using the distributive property. The distributive property multiplies both the numbers inside the parenthesis by the number that's on the outside of the parenthesis.
6x3 = 18, 6x4x=24x.
Hope this helps :) work hard!
8 0
3 years ago
Please prove this........​
Crazy boy [7]

Answer:  see proof below

<u>Step-by-step explanation:</u>

Given: A + B + C = π    →     C = π - (A + B)

                                    → sin C = sin(π - (A + B))       cos C = sin(π - (A + B))

                                    → sin C = sin (A + B)              cos C = - cos(A + B)

Use the following Sum to Product Identity:

sin A + sin B = 2 cos[(A + B)/2] · sin [(A - B)/2]

cos A + cos B = 2 cos[(A + B)/2] · cos [(A - B)/2]

Use the following Double Angle Identity:

sin 2A = 2 sin A · cos A

<u>Proof LHS → RHS</u>

LHS:                        (sin 2A + sin 2B) + sin 2C

\text{Sum to Product:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-\sin 2C

\text{Double Angle:}\qquad 2\sin\bigg(\dfrac{2A+2B}{2}\bigg)\cdot \cos \bigg(\dfrac{2A - 2B}{2}\bigg)-2\sin C\cdot \cos C

\text{Simplify:}\qquad \qquad 2\sin (A + B)\cdot \cos (A - B)-2\sin C\cdot \cos C

\text{Given:}\qquad \qquad \quad 2\sin C\cdot \cos (A - B)+2\sin C\cdot \cos (A+B)

\text{Factor:}\qquad \qquad \qquad 2\sin C\cdot [\cos (A-B)+\cos (A+B)]

\text{Sum to Product:}\qquad 2\sin C\cdot 2\cos A\cdot \cos B

\text{Simplify:}\qquad \qquad 4\cos A\cdot \cos B \cdot \sin C

LHS = RHS: 4 cos A · cos B · sin C = 4 cos A · cos B · sin C    \checkmark

7 0
3 years ago
Please help, thank you so much !!
Sliva [168]
Answer: x = 54

Explanation:

180 - 14 = 166

3x + 4 = 166
3x = 162
x = 162/3 = 54
6 0
2 years ago
Just give answers to blanck ones just give me The answers cause I don't want no explaining because I'm Savage
Airida [17]
Omg wow bruh #savageaf
6 0
3 years ago
Read 2 more answers
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