1) 5t^2 (1 + 6t)
2) 4x^3y^5 (5x + 2y)
3) (5r + 6x)(5r - 6x)
4) (x + 10)(x - 10)
5) (x - 3)^2
6) (x -5)(x - 3)
7) 3(16r^3 + 9)
8) 8(c^3 + 8d^3)
9) (2r - 125)(4r^2 + 250r + 15625)
10) (c + 3)(c - 1)
Answer:
-10
Step-by-step explanation:
Plugin the value of x.
y=1/6(-60)
y=-60/6
y=-10
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Answer:
D. 54
Step-by-step explanation:
Right angle = 90°
3/5 of 90°
3/5 × 90°
270 ÷ 5 = 54°
8x - 2y = 48, y =4
8x - 2(4) = 48
8x - 8 = 48
8x = 48+8
8x = 56
x = 56/8 = 7
x = 7
Angle AEB and angle CED are vertical angles, this means they equal each other, therefore we set their values as an equation and solve:
5x-10=3x+40
Subtract 3x to both sides
2x-10=40
Add 10 to both sides
2x=50
Divide both sides by 2
x=25
After we have gotten the value of x we can plug it in into the equation of angle AEB:
5x-10
Substitute x by 25
5(25)-10
Distribute
125-10
Substract
115
The measurement of angle AEB is 115
Hope it helped!, have a great day.