Solve for X. show your work. (x+2)(x+8)=0

4 tsp of baking soda and 1 Fl oz of vanilla. Which measurement is greater?

Sedbober [7]

Hey there! :D

We know that 6 tsp= 1 Fl Oz

4 tsp is less than 6 tsp.

Therefore, the vanilla has the greater measurement.

I hope this helps!
~kaikers

4 0

3 years ago

PLEASE HELP ME ON QUESTION 6b ASAP.

Serjik [45]

Answer:

y = - sin ( x )

X E R

..............

5 0

3 years ago

Find UV (Pic Stated Below)

natta225 [31]

Answer:

UV=29

Step-by-step explanation:

In right triangles AQB and AVB,

∠AQB = ∠AVB ...(i) {Right angles}

∠QBA = ∠VBA ...(ii) {Given that they are equal}

We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle

∠AQB+∠QBA+∠BAQ=180 ...(iii)

∠AVB+∠VBA+∠BAV=180 ...(iv)

using (iii) and (iv)

∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV

∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV (using (i) and (ii))

∠BAQ=∠BAV...(v)

Now consider triangles AQB and AVB;

∠BAQ=∠BAV {from (v)}

∠QBA = ∠VBA {from (ii)}

AB=AB {common side}

So using ASA, triangles AQB and AVB are congruent.

We know that corresponding sides of congruent triangles are equal.

Hence

AQ=AV

5x+9=7x+1

9-1=7x-5x

8=2x

divide both sides by 2

4=x

Now plug value of x=4 into UV=7x+1

UV=7*4+1=28+1=29

Hence UV=29 is final answer.

7 0

3 years ago

The regular price of the soccer ball is $25. During the sale, it is 20 percent off. Use ratio reasoning to find x, the amount th

Evgen [1.6K]

$ 5 is taken is off the regular price

Solution:

Given that, Regular price of the soccer ball is $ 25

During the sale, it is 20 percent off

Let "x" be the amount that is taken off the regular price

Regular price = $ 25

Discount = 20 percent off

Which means, 20 % of regular price is taken off

x = 20 % of regular price

x = 20 % of 25

$x = \frac{20}{100} \times 25\\\\x = 5$

Thus $ 5 is taken is off the regular price

3 0

4 years ago

work for a publishing company. The company wants to send two employees to a statistics conference. To be fair, the company deci

Yuki888 [10]

Answer:

(a) S = {MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC}

(b) The probability that Roberto and John attend the conference is 0.10.

(c) The probability that Clarice attends the conference is 0.40.

(d) The probability that John stays home is 0.60.

Step-by-step explanation:

It is provided that :

Marco (M), Roberto (R), John (J), Dominique (D) and Clarice (C) works for the company.

The company selects two employees randomly to attend a statistics conference.

(a)

There are 5 employees from which the company has to select two employees to send to the conference.

So the total number of ways to select two employees is:

${5\choose 2}=\frac{5!}{2!(5-2)!}=\frac{5\times 4\times 3!}{2\times 3!}=10$

The 10 possible samples are:

MR, MJ, MD, MC, RJ, RD, RC, JD, JC, DC

(b)

The probability of the event E is:

$P(E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = Total number of outcomes.

The variable representing the selection of Roberto and John is, RJ.

The favorable number of outcomes to select Roberto and John is, 1.

The total number of outcomes to select 2 employees is 10.

Compute the probability that Roberto and John attend the conference as follows:

$P(RJ)=\frac{n(RJ)}{N}=\frac{1}{10}=0.10$

Thus, the probability that Roberto and John attend the conference is 0.10.

(c)

The favorable outcomes of the event where Clarice attends the conference are:

n (C) = {MC, RC, JC and DC} = 4

Compute the probability that Clarice attends the conference as follows:

$P(C)=\frac{n(C)}{N}=\frac{4}{10}=0.40$

Thus, the probability that Clarice attends the conference is 0.40.

(d)

The favorable outcomes of the event where John does not attends the conference are:

n (J') = MR, MD, MC, RD, RC, DC

Compute the probability that John stays home as follows:

$P(J')=\frac{n(J')}{N}=\frac{6}{10}=0.60$

Thus, the probability that John stays home is 0.60.

4 0

3 years ago