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3 years ago

Which situation has a unit rate of $7?

Mathematics

1 answer:

cupoosta [38]3 years ago

4 0

Answer:

C is the answer.

Step-by-step explanation:

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The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin

NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, $\mu=8.04 g$

Standard deviation, $\sigma=0.08g$

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of machine components

$P(Xx_2)=0.03$

$P(X$

=0.03

From z- table we get

$P(Z1.88)=0.03$

Therefore, we get

$\frac{x_1-8.04}{0.08}=-1.88$

$x_1-8.04=-1.88\times 0.08$

$x_1=-1.88\times 0.08+8.04$

$x_1=7.8896$

$\frac{x_2-8.04}{0.08}=1.88$

$x_2=1.88\times 0.08+8.04$

$x_2=8.1904$

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0

3 years ago

Identify the rate of change of the function.

kati45 [8]

67Answer:67

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Is the ratio 4.2:1.5 proportional to the ratio 12:5

dezoksy [38]

Yes this is proportional!

3 0

3 years ago

The semiannual tuition payment at a major university is expected to be $30,000 for the 4 years beginning 18 years from now. What

elena-14-01-66 [18.8K]

Answer:

$49,216.78

Step-by-step explanation:

A(n,k) = R[1-(1+i)^-n / i) (1+i)^-k

A = Present value of deferred annuity

R = Payment at the end of period

R = 30,000

i = 0.06 / 2

n = (4)*2 = 8

k = deferred period, (18)*(2) = 36

A(n,k) = 30,000*(1-(1+0.04)-^8 / 0.04)*(1+0.04)^-36

A(n,k) = 30,000*(1-(1.04)^-8 / 0.04)*(1.04)^-36

A(n,k) = 30,000*(1 - 0.730690205/0.04) * 0.24366872185

A(n,k) = 30,000*(0.269309795 / 0.04)*0.24366872185

A(n,k) = 30,000*6.732744875*0.24366872185

A(n,k) = 49216.78014700164

A(n,k) = $49,216.78

So the lump sum payment that the university accept now is $49,216.78

6 0

3 years ago

Which equation is in standard form?

bulgar [2K]

keeping in mind that

standard form for a linear equation means

• all coefficients must be integers, no fractions

• only the constant on the right-hand-side

• all variables on the left-hand-side, sorted

• "x" must not have a negative coefficient

3x + 4y = 10.

8 0

3 years ago