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icang [17]
3 years ago
13

35w+9w+35w^3+25w^3–25w^3pls help

Mathematics
1 answer:
SVETLANKA909090 [29]3 years ago
8 0

Answer:

35w^3 + 44w

<em><u>Combine Like Terms:</u></em>

= 35w + 9w + 35w^3 + 25w^3 - 25w^3

= (35w^3 + 25w^3 - 25w^3) +(35w + 9w)

= 35w^3 + 44w

Hope this is right ♡

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Find (f – g)(x) if f(x) = 2x – 3 and g(x) = 4x + 8.
Aleks04 [339]

f(x) - g(x) = 2x-3 -(4x+8)

              = 2x-3 -4x-8

               = -2x-11

4 0
3 years ago
SOLUTION: a diver jumps from a diving board that is 24 feet above the water. the height of the diver is given by h= -16(t-1.5)(t
lara [203]

Answer:

The diver will hit the water at 1.5 seconds

Step-by-step explanation:

Given

h= -16(t-1.5)(t+1)

Required (Missing from the question)

When will the diver hit the water?

To do this, we simply solve for t

When the diver hits the water, the height is 0 (at that point)

So, substitute 0 for h in h= -16(t-1.5)(t+1)

0= -16(t-1.5)(t+1)

Divide both sides by -16

\frac{0}{-16} =\frac{-16(t-1.5)(t+1)}{-16}

\frac{0}{-16} =(t-1.5)(t+1)

0 =(t-1.5)(t+1)

(t-1.5)(t+1)=0

Split

t - 1.5 = 0 or t + 1 = 0

Solve for t

t = 1.5 or t = -1

But time (t) can not be negative.

So:

t = 1.5

Hence, the diver will hit the water at 1.5 seconds

8 0
3 years ago
What is the quotient of (4x^3-3x^2+5x+6) divided by (x+6)
musickatia [10]
The answer is in the picture below I used the square rooting method hope this is the answer you need!

3 0
3 years ago
A boat traveled 210 miles downstream and back. The trip downstream took 10 hours. The trip back took 70 hours. What is the speed
musickatia [10]

Try this solution:

Answer: 6 & 4.5 (m-per-h)

Step-by-step explanation:

- The basic formula used in this task is S=V*t, where S - distance, V - speed, t - time.

- the downstream speed is: V+Vc, where V - the speed of the boat in still water, Vc - the speed of the current.

- the upstream speed is: V-Vc.

- according to the described above the distance for downstream is S1=(V+Vc)*t1, where t1=10; the distance for upstream is S2=(V-Vc)*t2, where t2=70.

- for whole travel down- and upstream: S=S1+S2.

- Using these it is possible to make up the system of the equations:

\left \{ {{(70(V-V_c)=10(V+V_c)} \atop {70(V-V_c)+10(V+V_c)=210}} \right.

V - the speed of the boat in still water - 6 miles per hour, Vc - the speed of the current - 4.5 miles per hour. All the details for the system of the equations are in the attachment.

4 0
3 years ago
Natalie is shopping for new clothes and does not want to spend more than $65.
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The answer with Be B good choice
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