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2 years ago

Write the standard form of the equation of the circle with center (8,−1) that passes through the point (6,7)

Mathematics

1 answer:

marshall27 [118]2 years ago

5 0

Answer:

(x - 8)^2 + (y + 1)^2 = 68

Step-by-step explanation:

The standard form of the equation of the circle with center (8,−1) is :

(x - 8)^2 + (y + 1)^2 = R^2

If the circle passes through the point (6,7) that means that the point (6,7) is a solution of the equation and we can replace (x,y) with (6,7) to find R.

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Answer:

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3 years ago

17. The perimeter of each face of a Rubik's cube is

romanna [79]

A Rubik's cube is, well, a cube.

That means that each if its faces is a square, a quadrilateral with four right angles and four sides if the same length.

If the length of one side is x,

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Hope this helps!

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3 years ago

2. Given the equation of a circle in standard form, identify the center, radius, and graph the circle.

Varvara68 [4.7K]

Answer:

Center: ( -1 , 2 )

Radius: 6

Step-by-step explanation:

The equation for a circle is given as follow:

$(x-h)^{2} +(y-k)^{2} =r^{2}$

Where,

the Center is: ( h , k ) (note that the signs of the number are different)

and the radius is: r

So if we compare the original circle equation to the equation in the question we can see that:

$(x+1)^{2} +(y-2)^{2} =36$

the Center is: (-1,2)

and the radius is: $\sqrt{36}$ = 6

2. To draw the graph find points that lay on the circle, it's better to take the values of x and y from the Center:

first sub y=2 in the equation to find the values for x:

$(x+1)^{2} +(y-2)^{2} =36$

$(x+1)^{2} +(2-2)^{2} =36$

$(x+1)^{2} +(0)^{2} =36$

$(x+1)^{2} =36$

$x+1 =±\sqrt{36}$

$x=6-1$ AND $x=-6-1$

$x=5$ AND $x=-7$

The points are A(5,2) and B(-7,2)

second sub x= -1 in the equation to find the values for y:

$(x+1)^{2} +(y-2)^{2} =36$

$(-1+1)^{2} +(y-2)^{2} =36$

$(0)^{2} +(y-2)^{2} =36$

$(y-2)^{2} =36$

$y-2=±\sqrt{36}$

$y=6+2$ AND $y=-6+2$

$y=8$ AND $y=-4$

The points are D(-1,8) and E(-1,-4)

After finding the points write them in the graph and match them together to get the like the circle in the picture below:

8 0

3 years ago

What is the difference of the two polynomials?

ehidna [41]

(7y² + 6xy) - (-2xy + 3)

⇒ (-1 * -2xy) + (-1 * 3) = 2xy - 3

7y² + 6xy + 2xy - 3

7y² + 8xy - 3 Choice B.

5 0

3 years ago

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Hey bestie, here are some points :)<br> Smile more and stay hydrated fam.

exis [7]

Thank you so much, you too.

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2 years ago

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