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anygoal [31]
3 years ago
9

A container company makes small and large cylindrical cans. The area of the base is each 10cm squared. The volume of the smaller

can is 60cm cubee. The large can is 3 cm taller. What is the volume of the large can?
Mathematics
1 answer:
dsp733 years ago
7 0

Answer: The larger cylinder would 90cm^3

Step-by-step explanation:

If both have a base area of 10cm^3

Try to work the problem normally and just add the cube as your unit. 6cm is your height for the small cylinder so add 3 meaning the large will be 9cm tall. Then multiply, 10cm by 9cm = 90cm^3.

The formal is V=pi r^2 h

Hopefully this helps.

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How many ml of a 20% acid mixture and a 80% acid mixture should be mixed to get 120ml of a 35% acid mixture?
shutvik [7]

Answer:

Volume of Mixture A =90 ml

Volume of Mixture B =30 ml

Step-by-step explanation:

Let say, Mixture A + Mixture B = Mixture C

Volume of Mixture A is x

Volume of Mixture B is y

So, Volume of Mixture C is x+y = 120 ml

Now, Acid contain in Mixture A is 20% =0.2x

Acid contain in Mixture B is 80% =0.8y

Also, Acid contain in Mixture C is 35% =(0.35)(x+y) = 0.35×120=42

Now, we know that,

Acid contain of Mixture A + Acid contain of Mixture B=Acid contain of Mixture C

∴ 0.2x+0.8y=42

∴ 2x+8y=420

We get two linear equations

2x+8y=420 and x+y = 120

Solving above equation...

∴ x=120-y

Replacing x value in 2x+8y=420

∴ 2(120-y)+8y=420

∴ 240-2y+8y=420

∴ 6y=180

∴ y=30

Replacing y value in any equation

∴ x=120-y=120-30=90

∴ x=90

Thus,

Volume of Mixture A is x=90 ml

Volume of Mixture B is y=30 ml

3 0
4 years ago
What is simplified when -3(2x-y) + 2y+2(x+y) ?
S_A_V [24]

Answer: -x + 4y

Step-by-step explanation:

-3(2x-y) + 2y+2(x+y)

-6x + 3y + 2y + 2x + 2y

-6x + 2x +3y + 2y + 2y

-6x + 5x + 4y

-x + 4y

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3 years ago
Find the missing side lengths. Leave your answer as radicals in simplest form.
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B = 9
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Regards,
ArmyCee:)
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3 years ago
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MA_775_DIABLO [31]

Step-by-step explanation:

If the equation is

\sqrt{x + 2}

Then, here is the answer.

The definition of a derivative is

\frac{f(x + h) - f(x)}{h}

Also note that we want h to be a small, negligible value so we let h be a value that is infinitesimal small.

So we get

\frac{ \sqrt{x + h + 2} -  \sqrt{x + 2}  }{h}

Multiply both equations by the conjugate.

\frac{ \sqrt{x + h + 2} -  \sqrt{x + 2}  }{h}  \times  \frac{ \sqrt{x + h + 2} +  \sqrt{x + 2}  }{ \sqrt{x + h + 2} +  \sqrt{x + 2}  }  =  \frac{x + h + 2 - (x + 2)}{h \sqrt{x +  h + 2} +  \sqrt{x + 2}  }

\frac{h}{h \sqrt{x + h + 2}  +  \sqrt{x + 2} }

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Since h is very small, get rid of h.

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So the derivative of

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Part 2: If your function is

\sqrt{x}  + 2

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\frac{ \sqrt{x + h} + 2 - ( \sqrt{x}  + 2) }{h}

\frac{ \sqrt{x + h}  -  \sqrt{x} }{h}

\frac{x + h - x}{h( \sqrt{x + h}   +  \sqrt{x}) }

\frac{h}{h( \sqrt{x + h} +  \sqrt{x} ) }

\frac{1}{ \sqrt{x + h} +  \sqrt{x}  }

\frac{1}{2 \sqrt{x} }

So

\frac{d}{dx} (  \sqrt{x}  + 2) =  \frac{1}{2 \sqrt{x} }

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