Answer:
Andre has more money than Bob. If Andre gave Bob $20, they would have the same amount. While if Bob gave Andre $22, Andre would then have twice as much as Bob. How much does each one actually have?
Step-by-step explanation:
Here is the first sentence:
"If Andre gave Bob $20, they would have the same amount."
Algebraically:
1) x − 20 = y + 20.
(Andre -- x -- has the same amount as Bob, after he gives him $20.)
Here is the second sentence:
"While if Bob gave Andre $22, Andre would then have twice as much
as Bob."
Algebraically:
2) x + 22 = 2(y − 22).
(Andre has twice as much as Bob -- after Bob gives him $22.)
To solve any system of two equations, we must reduce it to one equation in one of the unknowns. In this example, we can solve equation 1) for x --
x − 20 = y + 20
implies x = y + 40
-- and substitute it into equation 2):
y + 40 + 22 = 2(y − 22).
That is,
y + 62 = 2y − 44,
y − 2y = − 44 − 62,
according to the techniques of Lesson 9,
−y = −106
y = 106.
Bob has $106. Therefore, according to the exression for x, Andre has
106 + 40 = $146.
I hope this helps u! :D
You'd need to convert feet into inches first. 2 feet is 24 inches. then add the other three inches. Juan's dog is 27 inches tall and Peters dog is 9 inches tall.
your fraction would be 27/9 which simplifies to 3.
Juan's dog is 3 times bigger than Peters!
Answer:
That would be about 11.667
(3x - 8)(3x + 8) is 3.) 9x^2 - 64
(x + 6)^2 is 4.) x^2 + 12x + 36
(3x - 2)(x + 5) is 1.) 3x^2 + 13x - 10
5x(x - 1)(x + 7) is 2.) 5x^3 + 30x^2 - 35x
(x - 8)(x + 7) is 5.) x^2 - 10x + 16
I hope this helps!
Answer:
the area is 6.5
Step-by-step explanation:
