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Sveta_85 [38]
4 years ago
8

Triangle ABC is translated using the rule (x, y) ? (x + 1, y ? 4) to create triangle A?B?C?. If a line segment is drawn from poi

nt A to point A? and from point B to point B?, which statement would best describe the line segments drawn?
Mathematics
1 answer:
Nikitich [7]4 years ago
4 0

Answer:

The line segments AA' and BB' are parallel and congruent

Step-by-step explanation:

we know that

When the transformation is a translation, the figure does not change its shape or dimensions,

so

AA'=BB'=CC'

therefore

The line segments AA' and BB' are parallel and congruent

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Please help with these few!!?​
nekit [7.7K]

Answer:

Triangle 6: 74

Triangle 7: 29

Triangle 8: 61

Triangle 9: 33

Step-by-step explanation:

Every triangle has a total degree angle of 180 degrees. Add the two sides that  are known and subtract the sum from 180 degrees to find out the last angle.

7 0
4 years ago
Find dy/dx by implicit differentiation for ysin(y) = xcos(x)
tatyana61 [14]

Answer:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

Step-by-step explanation:

So we have:

y\sin(y)=x\cos(x)

And we want to find dy/dx.

So, let's take the derivative of both sides with respect to x:

\frac{d}{dx}[y\sin(y)]=\frac{d}{dx}[x\cos(x)]

Let's do each side individually.

Left Side:

We have:

\frac{d}{dx}[y\sin(y)]

We can use the product rule:

(uv)'=u'v+uv'

So, our derivative is:

=\frac{d}{dx}[y]\sin(y)+y\frac{d}{dx}[\sin(y)]

We must implicitly differentiate for y. This gives us:

=\frac{dy}{dx}\sin(y)+y\frac{d}{dx}[\sin(y)]

For the sin(y), we need to use the chain rule:

u(v(x))'=u'(v(x))\cdot v'(x)

Our u(x) is sin(x) and our v(x) is y. So, u'(x) is cos(x) and v'(x) is dy/dx.

So, our derivative is:

=\frac{dy}{dx}\sin(y)+y(\cos(y)\cdot\frac{dy}{dx}})

Simplify:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}

And we are done for the right.

Right Side:

We have:

\frac{d}{dx}[x\cos(x)]

This will be significantly easier since it's just x like normal.

Again, let's use the product rule:

=\frac{d}{dx}[x]\cos(x)+x\frac{d}{dx}[\cos(x)]

Differentiate:

=\cos(x)-x\sin(x)

So, our entire equation is:

=\frac{dy}{dx}\sin(y)+y\cos(y)\cdot\frac{dy}{dx}}=\cos(x)-x\sin(x)

To find our derivative, we need to solve for dy/dx. So, let's factor out a dy/dx from the left. This yields:

\frac{dy}{dx}(\sin(y)+y\cos(y))=\cos(x)-x\sin(x)

Finally, divide everything by the expression inside the parentheses to obtain our derivative:

\frac{dy}{dx}=\frac{\cos(x)-x\sin(x)}{\sin(y)+y\cos(y)}

And we're done!

5 0
3 years ago
Can anyone help me with this
marin [14]

Answer:

27

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Which decimal is the greatest?
tankabanditka [31]
3.2591 is the greatest
5 0
4 years ago
Read 2 more answers
Find the midpoint of the line segment joining the points R(-5,5) and S(4.6).
tigry1 [53]

Hey there! I'm happy to help!

To find the x value of the midpoint, you add the x values and divide by 2.

-5+4=-1

-1/2=-1/2

For the y value, you add the y values and divide by 2.

5+6=11

11/2=5 1/2

So, the midpoint is (-1/2, 5 1/2).

Have a wonderful day! :D

6 0
3 years ago
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