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Bess [88]
3 years ago
12

If 6 families share 20 pounds of ham, between what two whole numbers will each family share

Mathematics
1 answer:
zubka84 [21]3 years ago
6 0

Answer:

3

Step-by-step explanation:

According to the question

6 families shared 20 pounds

1 family share x pound

Cross multiply

6x=20

Divide both sides by 6

x=3.333

Nearest to whole number

x=3

Therefore x=3

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For the feasibility region shown below, find the maximum value of the function P=2x+3y.
timofeeve [1]
Corner points in this graph are: ( 0,0 ) ( 0,8 ) ( 5,6 ) and ( 8, 0 ).
If we plug those values in : P = 2 x + 3 y
P ( 0,0 )= 0
P ( 0,8 ) = 2 * 0 + 3 * 8 = 24
P ( 6 , 5 ) = 2 * 6 + 3 * 5 = 12 + 15 = 27
P ( 8 , 0 ) =  2 * 8 + 3 * 0 = 16
The maximum value is:
P max ( 6 , 5 ) = 27
3 0
3 years ago
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Help me w the answer
Olin [163]
I have no clue. im on that same question
3 0
3 years ago
X is number of 1$ bills 1/2x =20
SOVA2 [1]
If your trying to solve for x it’s 40, x=40
2 times 1/2x =2x20
x=2x20
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4 0
4 years ago
Five cats each ate 1/4 cup of cat food. How much food did the five cats eat?
qaws [65]

Answer:  Five cats ate 1 and a quarter of cat food.


Step-by-step explanation

Given:-

Cat food ate by one cat = 1/4 cup

Cat food ate by five cats =5\times \frac{1}{4} \text{ [Multiplying both sides with 5 ]}\\\\=\frac{5}{4}=\frac{4+1}{4}=\frac{4}{4}+\frac{1}{4}=1+\frac{1}{4}=1 and 1/4 cup.

Therefore cat food ate by five cats = 1 and a quarter of cup.[ here a quarter =1/4]

7 0
3 years ago
“the perimeter of the rectangle below is 90 units. find the length of side PS. write your answer without variables.”
Rzqust [24]

Answer:

19

Step-by-step explanation:

The opposite sides are equal, so:

PS = 3y+1

RS = 4y+2

QR = 3y+1

PQ = 4y+2

Therefore, we can set the perimeter 90 = PS+RS+QR+PQ

90 = (3y+1) + (4y+2) + (3y+1) + (4y+2), or,

90 = 2(3y+1) + 2(4y+2)

90 = 6y+2 + 8y+4

90 = 14y + 6

84 = 14y

y = 6

Then, we go back to the question. It's asking for the length of PS. PS = 3y+1, so we plug in 6 for y

3(6)+1

18 + 1 = <u>19</u>

5 0
3 years ago
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