Answer:
q = 4
Step-by-step explanation:
given p and q vary inversely then the equation relating them is
p = ← k is the constant of variation
to find k use the condition p = 29 when q = 16 , then
29 = ( multiply both sides by 16 )
464 = k
p = ← equation of variation
when p = 116 , then
116 = ( multiply both sides by q )
116q = 464 ( divide both sides by 116 )
q = 4
Answer:
The minimum sample size we should anticipate using is 601.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
We have no history with this characteristic, so we have no idea as to what the proportion might be.
This means that we use , which is when the largest sample size will be needed.
95% confidence level
So , z is the value of Z that has a pvalue of , so .
What is the minimum sample size we should anticipate using?
This is n for which M = 0.04. So
Rounding up, 601
The minimum sample size we should anticipate using is 601.
Answer:
test statistic, z = −1.74
Step-by-step explanation:
given data
students n = 100
mean time x = 41.13 seconds
σ = 5
we consider µ = 42
solution
we get here The test statistic that is express as
test statistic, z = ......................1
put here value and we will get
test statistic, z = \frac{41.13-42}{\frac{5 }{\sqrt{100}}}
test statistic, z = −1.74
Answer:
7 − (6 ⋅ 3) + 2
Step-by-step explanation:
7 − 6 ⋅ 3 + 2
PEMDAS says we need to multiply before we add and subtract
7 − (6 ⋅ 3) + 2
Answer:
Step-by-step explanation:
3^2 + 1^2 = c^2 (diagonal squared)
9 + 1 = c^2
10 = c*2
is the length
It is irrational because the decimal repeats forever