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2 years ago

In how many ways can four aces be drawn from a deck of cards? (Order is not important.)

1 answer:

8 0

Let's imagine that we have in the deck 52 cards. So what we need to do is to make a kind of "progression".So let me explain this by doing the procedure. we can use is like this:
4/52 * 3/51 * 2/50 * 1/49 =
24 / 6497400 = 
1 / 270725 
3.694e-6

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At the market, Meyer buys a

ZanzabumX [31]

Answer:

Pounds of bananas purchased is 3.

Step-by-step explanation:

Purchased price of bananas is 6.04 − 4.99 = $ 1.05

Pounds of bananas purchased is 1.05 0.35 = 3 pounds

Hope this helps!!!

6 0

2 years ago

Please help I’m so stressed over this ok here it is it cost $12.50 to enter an amusement park and $1.50 to play each game. Solve

jeyben [28]

Answer:
He can go on 15 gams

3 0

2 years ago

What translation rule can be used to describe the result of the composition of T < 4, −10 >(x, y) and T < −1, −9 >(x

Vikki [24]

The first translation picks a point and adds 4 to its x coordinate, and subtracts 10 from the y coordinate. In other words, it moves the point 4 units to the right and 10 units down.

Similarly, the second translation subtracts 1 to the x coordinate, and subtracts 9 from the y coordinate. In other words, it moves the point 1 unit to the left and 9 units down.

So, if you perform one translation after the other, you move the point 4 units to the right and 1 unit to the left along the x axis, and 10 units down and 9 more units down along the y axis.

The net result is a translation of 3 units to the right and 19 units down.

6 0

2 years ago

Am solving this problem correct

cestrela7 [59]

A) The degree of the first term is... 1
$first \ term = 3t$
The degree of the second term is... 2
$second \ term = t^2$
The degree of the third term is... 4
$third \ term = t^4$

b) The leading term of the polynomial is... 7t⁴
The leading coefficient of the polynomial is... 7

c) The degree of the polynomial is... 4

6 0

2 years ago

Read 2 more answers

Consider the following theorem and proof.Theorem: The number âš2 is not rational number.Proof: Let's suppose âš2 is a rational n

ololo11 [35]

Answer:

The statement "Both of the numbers a and b cannot be even." is justified by the fact that a/b is simplified lowest terms

Step-by-step explanation:

We need to show that the √2 is an irrational number.

And from the given steps of proof stated in the question, we need to find the assumption that justifies the fact : " Both of the number a and b cannot be even".

First take the given options :

Option a : √2 is a rational number

√2 being an rational or irrational has no relation of a and b to be even or odd. So, this option is rejected.

Option B : a/b is simplified lowest terms

This shows that a and b are not even because if a and b are even then a/b can be simplified in other lowest term.

Option c : √2 is a irrational number

Similarly, By using the inverse part of Option A, option c is also rejected.

Option d : The fact that b divides a evenly

This only shows that the a is even. This does not give any idea about b is even or not. So option D is also rejected.

Option E : The fact that a and b are whole numbers

This fact does not imply that the a and b are even or odd. So option E is also rejected.

Hence, The statement "Both of the numbers a and b cannot be even." is justified by the fact that a/b is simplified lowest terms

7 0

2 years ago