All categories

2 years ago

Can any one please help me with these Math questions soon as possible?

Mathematics

1 answer:

disa [49]2 years ago

7 0

Answer:

the answer to the first question is 9/27, 5/27, 13/27

the answer to the second question is 27/126, 33/126, 20/126, 42/126

the answer to the last question is 32/44

Step-by-step explanation:

they way you solve the fist two questions you just add the numbers up and that will tell you your probability.

for the last question you take the number of players and subtract it by 12 to get the top number

You might be interested in

Three dumpsters are delivering sand to a golf course

timofeeve [1]

Answer:

10,000 tons of sand is being delivered.

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

What is the number below that subtracted 7 from four times it multiplied and equals 1?

Dvinal [7]

Answer:

a.4

Step-by-step explanation:

because

4 0

2 years ago

On his outward journey, Ali travelled at a speed of s km/h for 2.5 hours. On his return journey, he increased his speed by 4 km/

den301095 [7]

Answer:

3.08 km/h.

Step-by-step explanation:

We know that,

$Speed=\dfrac{Distance}{Time}$

Ali traveled at a speed of s km/h for 2.5 hours.

Let d be the distance and t be the time.

$2.5=\dfrac{d}{t}$

$2.5t=d$ ...(1)

On his return journey, he increased his speed by 4 km/h and saved 15 minutes. So, distance is d and times is t-15.

$4=\dfrac{d}{t-15}$

$4(t-15)=d$ ...(2)

From (1) and (2), we get

$4(t-15)=2.5t$

$4t-60-2.5t=0$

$1.5t=60$

$t=40$

Put t=40 in (1).

$d=2.5(40)=100$

So, t=40 and d=100.

Now,

Total distance = d + d = 100 + 100 = 200

Total time = t + t - 15 = 40 + 40 - 15 = 65

So, the average speed is

$\text{Average speed}=\dfrac{\text{Total distance}}{\text{Total time}}$

$\text{Average speed}=\dfrac{200}{65}$

$\text{Average speed}\approx 3.08$

Therefore, the average speed is 3.08 km/h.

3 0

3 years ago

Divide. 3/5 \1/4 A. 3/20 B. 5/12 C. 4/9 D. 2 2/5

KIM [24]

Its letter A 3/20 i divided it

4 0

3 years ago

Find \tan\left(\frac{17\pi}{12}\right)tan( 12 17π )tangent, left parenthesis, start fraction, 17, pi, divided by, 12, end frac

uranmaximum [27]

One way to do this is to notice

$\dfrac{17\pi}{12}=\dfrac\pi6+\dfrac{5\pi}4$

Then

$\tan\dfrac{17\pi}{12}=\tan\left(\dfrac\pi6+\dfrac{5\pi}4\right)=\dfrac{\tan\frac\pi6+\tan\frac{5\pi}4}{1-\tan\frac\pi6\tan\frac{5\pi}4}$

We have

$\tan\dfrac\pi6=\dfrac{\sin\frac\pi6}{\cos\frac\pi6}=\dfrac{\frac12}{\frac{\sqrt3}2}=\dfrac1{\sqrt3}$

and since $\tan x$ has a period of $\pi$ ,

$\tan\dfrac{5\pi}4=\tan\left(\pi+\dfrac\pi4\right)=\tan\dfrac\pi4=1$

and so

$\tan\dfrac{17\pi}{12}=\dfrac{\frac1{\sqrt3}+1}{1-\frac1{\sqrt3}}=\dfrac{1+\sqrt3}{\sqrt3-1}=2+\sqrt3$

7 0

3 years ago