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yKpoI14uk [10]
3 years ago
12

A company produces metal slabs for industrial use. the slabs come in 3 thicknesses: 5in, 10in, and 15in. the weights of each thi

ckness for each metal are given below. metal 1: 150lbs, 300lbs, 600lbs metal 2: 130lbs, 260lbs, 390lbs metal 3: 310lbs, 620lbs, 930lbs metal 4: 140lbs, 280lbs, 420lbs for which of the metals is weight not proportional to thickness
Mathematics
2 answers:
Len [333]3 years ago
5 0

Given slabs thicknesses 5in, 10in, and 15in.

Therefore,<u> </u><u>ratio of thicknesses in simplest form would be 1:2:3.</u>

Metal 1 thicknesses =  150lbs, 300lbs, 600lbs

Dividing by 150, we get ratio of Metal 1 thicknesses = 1:2:4.

Metal 2 thicknesses = 130lbs, 260lbs, 390lbs.

Dividing by 130, we get ratio of Metal 2 thicknesses =  1:2:3.

Metal 3 thicknesses = 310lbs, 620lbs, 930lbs.

Dividing by 310, we get ratio of Metal 3 thicknesses = 1:2:3.

Metal 4 thicknesses = 140lbs, 280lbs, 420lbs.

Dividing by 140, we get ratio of Metal 4 thicknesses = 1:2:3.

<u>We can see the ratios of thicknesses of Metal 1 are 1:2:4 but it should be 1:2:3.</u>

Therefore, Metal 1 weight is not proportional to thickness.


vfiekz [6]3 years ago
5 0

Answer:

Weights of metal 1 is not proportional to thickness.

Step-by-step explanation:

We have been given 3 thicknesses of metal slabs and the weights of each thickness for each metal. We are asked to find out which of the metals weight is not proportional to thickness.

We can see that the thicknesses of slabs are first three multiples of 5 that is 5 inches, 10 inches and 15 inches.

Now let us see which of the metals have not their weights proportional to their thicknesses.

In our first option we can see that 300 is 2 times 150 and 600 is 4 times 150 which is not proportional to thickness. In order to metal 1's weight to be proportional with it's thickness it should be 450 lbs instead of 600.

Our second metal's weight is proportional to it's thickness as 130, 260 and 390 are 3 first consecutive multiples of 130.

Our third and fourth metal's weights are also proportional to their thicknesses.

Therefore, metal 1's weight is not proportional to thickness.

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We want to determine the equation in point slope form for the line that is perpendicular to the given line and passing through the point (5.6) .

The equation and the point is;

y=\frac{2}{3}x+9,(5,6)

We know that for two lines to be perpendicular, the product of their slopes should be -1.

Therefore, the slope of the perpendicular should be;

m=-\frac{1}{(\frac{2}{3})}=-\frac{3}{2}

The second condition is that the line must pass through the point (5,6) , to do thid, we write the equation of the line in point slope form which is;

y-y_1=m(x-x_{1_{}})

Inserting all values, we have,

y-6=.-\frac{3}{2}(x-5)

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6 0
1 year ago
PLS QUICK I ONLY HAVE 2 HOURS
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Answer:

D

Step-by-step explanation:

As you can observe from the pattern, the numerator gets multiplied by 4 every increase in the sequence.

So , clearly, the 5th term will be = \frac{64*4}{5} =\frac{256}{5}

and the 6th term will be = \frac{256*4}{5} =\frac{1024}{5}

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6 0
1 year ago
Huan's wage is £10.40 per hour l. he receives a 10% pay rise ​
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Answer:

Step-by-step explanation:

10% of 10.40=1.04

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8 0
2 years ago
Find the sum of first 20 to terms of an ap in which d is equal to 7 and 20 second term is 149​
GuDViN [60]

Answer:

1370

Step-by-step explanation:

<h3>Given</h3>
  • AP with d= 7 and a₂₂ = 149
<h3>To find</h3>
  • Sum of first 20 terms
<h3>Solution</h3>

<u>First, let's get the value of the first term:</u>

  • aₙ = a + (n-1)d
  • a₂₂ = a + 21d
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<u>Next, let's find the sum of the first 20 terms</u>

  • Sₙ = 1/2n(2a+ (n-1)d)
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<u>Answer is</u> 1370

6 0
3 years ago
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