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3 years ago

The sum of four consecutive numbers is 186. What is the second smallest number?

Mathematics

2 answers:

lord [1]3 years ago

8 0

Answer:

Need more info

Step-by-step explanation:

pentagon [3]3 years ago

4 0

Answer:

46 is the second smallest number of the sequence

Step-by-step explanation:

Let's write the sum of 4 consecutive numbers (starting at the value x) as:

x + (x + 1) + (x + 2) + (x + 3) = 186

Now group all the unknowns:

x + x + x + x + 1 + 2 +3 = 186

4 x + 6 = 186

4 x = 186 - 6

4 x = 180

x = 180/4

x = 45

Then the sequence was: 45, 46, 47, 48

and the second smallest number of the sequence s: 46

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iren2701 [21]

The values are $A=8, B=5, C= 20$ and $D=3$

Explanation:

The expression is $4x^{2} (2x^{3} +5x)=Ax^{B} +Cx^{D}$

Simplifying, we get,

$8x^{5} +20x^3=Ax^{B} +Cx^{D}$

Since, both sides of the expression are equal, we can equate the corresponding values of A, B, C and D.

Thus, we get,

$8 x^{5}=A x^{B}$ ⇒ $A=8$ and $B=5$

Also, equating, $20 x^{3}=C x^{D}$ , we get,

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