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Alika [10]
4 years ago
13

The sum of four consecutive numbers is 186. What is the second smallest number?

Mathematics
2 answers:
lord [1]4 years ago
8 0

Answer:

Need more info

Step-by-step explanation:

pentagon [3]4 years ago
4 0

Answer:

46 is the second smallest number of the sequence

Step-by-step explanation:

Let's write the sum of 4 consecutive numbers (starting at the value x) as:

x + (x + 1) + (x + 2) + (x + 3) = 186

Now group all the unknowns:

x + x + x + x + 1 + 2 +3 = 186

4 x + 6 = 186

4 x = 186 - 6

4 x = 180

x = 180/4

x = 45

Then the sequence was: 45, 46, 47, 48

and the second smallest number of the sequence s: 46

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Leya [2.2K]
No matter the number of times you rolled the dice, the probability of getting a number is always 1/6. But here we can choose 4 numbers ( 1 to 4) hence the probability P( 1 or 2 or 3 or 4) = 4/6 2/3  = 0.6667 = 66.67% (A)


4 0
3 years ago
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-13r + -4r + 14r -9 =-15
deff fn [24]

Answer:

2

Step-by-step explanation:

-13 x 2 = -26

-4 x 2 = -8

14  x 2 = 28

-26 + -8 + 28 +-9 = -15

have a nice day and mark me brainliest! :)

8 0
3 years ago
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Find the dicontinuities of the function.
elena-s [515]

Answer:

Step-by-step explanation:

I'm assuming you meant to type in

f(x)=\frac{x^2+12x+27}{x^2+4x+3} because you can only have removable discontinuities where there is a rational (fraction) function. Begin by factoring both the numerator and denominator to

f(x)=\frac{(x+3)(x+9)}{(x+1)(x+3)} and cancelling out like terms would have us eliminating the (x + 3). That is where there is a removable discontinuity. It leaves a hole. The other discontinuity, (x + 1) doesn't cancel out so it is a non-removable discontuinity, which is a vertical asymptote.

The removable discontinuity is at -3. There is no y value at x = -3 (remember there's only a hole here), because -3 causes the denominator to go to 0 and we all know that having a 0 in the denominator of a fraction is a big no-no!!!

5 0
3 years ago
I can’t figure out, can someone please explain how to get the correct answer?
Karolina [17]

Answer:

  a)  CD = 9

  b)  AB = 20

Step-by-step explanation:

<h3>a)</h3>

In this geometry, all of the right triangles are similar. This means The ratio of short side to long side is the same for all of the triangles.

You are given the short and long sides of ΔADB, and the long side of ΔCDA. You are asked for the short side of ΔCDA, so you can write the proportion ...

  CD/AD = AD/BD

  CD/12 = 12/16

  CD = 12(12/16)

  CD = 9

__

<h3>b)</h3>

There are a couple of options for finding AD. One you may be familiar with is the Pythagorean theorem.

  AB² = AD² +DB²

  AB² = 12² +16² = 144 +256 = 400 . . . . fill in known values

  AB = √400 = 20 . . . . . take the square root

__

Alternatively, you can use the same proportional relationship that is described above. Here, we make use of the ratio of the hypotenuse to the long side.

  AB/BD = CB/AB

  AB² = BD·CB = 16·(16+9) = 16·25 . . . . cross multiply; fill in known values

  AB = √(16·25) = 4·5 . . . . . take the square root

  AB = 20

_____

<em>Additional comment</em>

This geometry, where the altitude of a right triangle is drawn, has some interesting properties. We have hinted at them above.

You can write three sets of proportions for this geometry: the ratios of short side and long side; the ratios of short side and hypotenuse; and the ratios of long side and hypotenuse. When you look at the way the sides touching the longest hypotenuse relate to that hypotenuse, you see three similar relations:

  AC = √(CD·CB)

  AD = √(DC·DB)

  AB = √(BD·BC) . . . . . . . . the relation used in part (b) above

This "square root of a product" is called the <em>geometric mean</em>. In effect, the length of a side touching the longest hypotenuse is the geometric mean of the two segments of that hypotenuse that it touches.

7 0
2 years ago
What is the gcf of 27 and 36
mestny [16]

The answer would be 9. 9x3=27 and 9x4=36. Although 3 fits into both, 9 is the BIGGER number that also fits into both of the numbers shown in the problem.

5 0
3 years ago
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