The answer is <span>B. y = x^3 + 4x^2 + 2x - 2
A line that passes through all given point is the correct choice. Now, substitute x and y in all of the choices:
</span>B. y = x³ + 4x²<span> + 2x - 2
Point 1: </span><span>(-2, 2)
x = -2
y = 2
____
2 = (-2)</span>³ + 4 *(-2)² + 2 * (-2) - 2
2 = -8 + 4 * 4 + (-4) - 2
2 = -8 + 16 - 4 - 2
2 = 2
_____
Point 2: (-1, -1)
x = -1
y = -1
____
-1 = (-1)³ + 4 *(-1)² + 2 * (-1) - 2
-1 = -1 + 4 * 1 + (-2) - 2
-1 = -1 + 4 - 2 - 2
-1 = -1
____
Point 3: (1, 5)
x = 1
y = 5
____
5 = (1)³ + 4 *(1)² + 2 * 1 - 2
5 = 1 + 4 * 1 + 2 - 2
5 = 1 + 4 + 2 - 2
5 = 5
____
Point 4: (3, 67)
x = 3
y = 67
____
67 = (3)³ + 4 *(3)² + 2 * (3) - 2
67 = 27 + 4 * 9 + 6 - 2
67 = 27 + 36 + 6 - 2
67 = 67
So, line B passes through all choices.
The object should be placed 20/cm from the lens so as to form its real image on the screen
<h3>Mirror equation</h3>
The mirror equation is given according to the expression below;
1/f = 1/u + 1/v
where
f is the focal length
u is the object distance
v is the image distance
Given the following parameters
f = 5cm
v = 20cm
Required
object distance u
Substitute
1/5 = 1/u +1/20
1/u = 1/5-1/20
1/u = 3/20
u = 20/3 cm
Hence the object should be placed 20/cm from the lens so as to form its real image on the screen
Learn more on mirror equation here; brainly.com/question/27924393
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First,
149,500 * .10 = 14,950
149,500 - 14,950 = 134,550
then,
134,550 * .05 = 6727.50
134,550 - 6727 = 127,822.55
127,822.50 * .04 = 5112.90
trade discount = 14950 + 6727.50 + 5112.90
26790.40
hope this help
Base on my research there are ways to get the number of roots. If you are looking for negative roots and even the positive one has their own ways. But in this problem, we just need to determine the total number of roots of a polynomial. In determining the total number of roots, you just need to find the degree of the polynomial function. The degree refers to the highest exponent of the polynomial. Therefore, in the function given, 6 is the degree of the polynomial function. The total number of roots is 6.
