All will apply except for (A, C, and E) because those lengths are less than 4/6. So (B, D and F) are the correct answers.
Answer:
A maximum of 43 students and 11 teachers can go to the trip.
Step-by-step explanation:
Since a group of teachers and students will take a bus trip to a museum, and each teacher will lead a group of no more than 4 students, and the bus can hold a maximum of 54 teachers and students, to determine the possible numbers of teachers and students who can go on the trip, the following calculation must be performed:
4 + 1 = 5
54/5 = X
10.8 = X
10 x 4 = 40
10 x 1 = 10
4 - 1 = 3
Therefore, a maximum of 43 students and 11 teachers can go to the trip.
So let's start from the beginning.
Add 2 and 4:
(2 + 4)
Multiply the sum by 3:
3(2 + 4)
Then add 5 to that product:
3(2 + 4) + 5
Then double the results:
2[3(2 + 4) + 5]
Answer:
3
Step-by-step explanation:
look at the sides
