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3 years ago

What is the answer to this problem?

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

4 0

The answer is 24 since it is the least common multiple

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Douglas said he can find 240÷10 by taking the 0 off 240 to get 24. Douglas finds 59.20÷10 using the same method and gets 59.2. U

Lady bird [3.3K]

Answer:

Douglas is incorrect

Step-by-step explanation:

We can remove a zero from a number that has a zero on the right of the decimal place if that zero is the last number before the decimal place. This is true for 240 divided by 10 because the zeros cancel out:

$=240/10=24$

In 59.20 this is not true. Dividing a number with a decimal place requires the decimal place to move and not cancel out the zero after the decimal place. Therefore:

$=59.20/10=5.92$

3 0

3 years ago

What is 5/15 + 5? I have to write 20 charecters so idk what else to say.

djverab [1.8K]

Answer:

$\frac{16}{3}$

Step-by-step explanation:

$\frac{5}{15} + 5$

$\frac{1}{3} + 5$

$\frac{1}{3} + \frac{15}{3}$

$\frac{1+15}{3}$

$\frac{16}{3}$

5 0

3 years ago

Read 2 more answers

Frank works in the supply room of a law firm. At the beginning of the month, he had 21 boxes of pens with 13 pens in each box. A

Natali [406]

It would be C.228 am I right or wrong?

5 0

3 years ago

Read 2 more answers

How do you solve this problem: 5(x3)-(-20)

Nimfa-mama [501]

First step: multiply the 5(x3) and it will give you x15 or most commonly written as 15x. you should now have 15x-(-20).

Second step: since you cannot subtract -20 from 15x because it has a variable, the final answer is just 15x-(-20), or 15x+20.

8 0

3 years ago

X^2 + 32x + 256 = 1<br>please show steps

Elena L [17]

$\boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}$

<h2>Explanation:</h2>

In this case, we have the following equation:

$x^2+32x+256=1$

But we can write this equation as:

$x^2+32x+256=1 \\ \\ Subtract \ -1 \ from\ both \ sides: \\ \\ x^2+32x+256-1=1-1 \\ \\ x^2+32x+255=0$

So this final result is a quadratic equation written in Standard Form ( $ax^2+bx+c=0$ ). We need to find the solutions to this equations, so let's use quadratic formula:

$x=\frac{-b \pm \sqrt{b^2-4ac}}{2a} \\ \\ a=1 \\ b=32 \\ c=255 \\ \\ \\ x=\frac{-32 \pm \sqrt{(32)^2-4(1)(255)}}{2(1)} \\ \\ x=\frac{-32 \pm \sqrt{1024-1020}}{2} \\ \\ x=\frac{-32 \pm \sqrt{4}}{2} \\ \\ x=\frac{-32 \pm 2}{2} \\ \\ Finally, \ two \ solutions: \\ \\ \boxed{x_{1}=-15} \\ \\ \boxed{x_{2}=-17}$

<h2>Learn more:</h2>

Quadratic Equations: brainly.com/question/10278062

#LearnWithBrainly

3 0

3 years ago