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svetlana [45]
4 years ago
7

Write the equation of a line parallel to the line whose equation is 3y+5x=6 and whose y-intercept is4

Mathematics
1 answer:
victus00 [196]4 years ago
5 0

Answer:

Step-by-step explanation:

Step 1:  rewrite the equation of the given line in to slope-intercept form by solving for y

  3y + 5x = 6    

     3y = -5x + 6               (subtract 5x from both sides)

        y = -(5/3)x + 2           (divide both sides by 3)

Step 2:  Our line is parallel to this line, so it has the same slope, and a

y-intercept of 4, so we have...

  y = -(5/3)x + 4      

*slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept,

 

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