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3 years ago

Find the value of x to the nearest tenth. 9.0 8.6 26.3 5.7

Mathematics

1 answer:

Ket [755]3 years ago

5 0

Answer: x = 9.0

Step-by-step explanation:

From the given right angle triangle,

the hypotenuse of the right angle triangle is x

With m∠39 as the reference angle,

the adjacent side of the right angle triangle is 7

The unknown side represents the opposite side of the right angle triangle.

To determine x, we would apply

the cosine trigonometric ratio which is expressed as

Cos θ = adjacent side/hypotenuse. Therefore,

Cos 39 = 7/x

x = 7/cos 39 = 7/0.777

x = 9.0 to the nearest tenth

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Determine whether each exponential equation is a decay or a growth.

kolezko [41]

Answer:

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Step-by-step explanation:

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2 years ago

X+2y - 3z =15. 2x – 2z=6 x = 3. 2/3)-22 i dont know this answer pls help me???

kondor19780726 [428]

Answer(s):

Exact Form: x + 2 y − 3 z = 15 , 2 x − 2 z = 6 , 3 2 3

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2 years ago

When a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a ra

Sergeu [11.5K]

Answer:

$r=\sqrt{10}\text{ m}$

Step-by-step explanation:

We have been given that when a cylindrical tank is filled with water at a rate of 22 cubic meters per hour, the level of water in the tank rises at a rate of 0.7 meters per hour. We are asked to find the approximate radius of tank in meters.

We will use volume of cylinder formula to solve our given problem as:

$V=\pi r^2h$ , where,

r = Radius,

h = Height of cylinder.

Since the level of water in the tank rises at a rate of 0.7 meters per hour, so height of cylinder would be $h = 0.7$ meters at $V=22\text{ m}^3$ .

Upon substituting these values in above formula, we will get:

$22\text{ m}^3=\frac{22}{7}\cdot r^2(0.7\text{ m})$

$22\text{ m}^3=\frac{22}{10}\cdot r^2\text{ m}$

$\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}=r^2$

$r^2=\frac{10}{22}\cdot\frac{22\text{ m}^3}{\text{m}}$

$r^2=10\text{ m}^2$

Now, we will take positive square root of both sides as radius cannot be negative.

$\sqrt{r^2}=\sqrt{10\text{ m}^2}$

$r=\sqrt{10}\text{ m}$

Therefore, radius of tank would be approximately square root of 10 m.

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2 years ago

Line j passes through points 1,6 and 7,1 line k is parallel to line j. What is the slope of line k?

Mashutka [201]

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