Answer:
In 286 different ways 10 players can be selected.
Step-by-step explanation:
There are 6 girls and 7 boys in a class. So in total there are 6+7 = 13 number of students in the class.
A team of 10 players is to be selected from the class.
As there is no other conditions are given, we can pick any 10 students from 13 students.
The way we can select 10 players from 13 students is;
= (13 10)
= 13!/10!(13-10)!
= 13!/10! 3!
= (13 × 12 × 11 × 10!)/ 10! 3!
= ( 13 × 12 × 11)/6
= 286
The possible digits are:
5, 6, 7, 8 and
9. Let's mark the case when the locker code begins with a prime number as
A and the case when <span>the locker code is an odd number as
B. We have
5 different digits in total,
2 of which are prime (
5 and
7).
First propability:
</span>

<span>
By knowing that digits don't repeat we can say that code is an odd number in case it ends with
5, 7 or
9 (three of five digits).
Second probability:
</span>
Step-by-step explanation:
S + L = 6 => L= 6-S
8S + 10L = 56
8S + 10(6-S) = 56
8S +60 -10S = 56
-2S = 56-60
-2S = -4
S = -4/-2
S = 2
=> S = small notebook = 2
L = large notebook = 6-2 = 4
Answer:3.5
Step-by-step explanation:
5 times 3.5 = 17.5