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Scrat [10]
2 years ago
13

What is the value of x?

Mathematics
2 answers:
Advocard [28]2 years ago
8 0

Answer:

\boxed{x \degree = 9 \degree}

Step-by-step explanation:

=  > 90\degree + 57\degree + (3x + 6)\degree = 180\degree \\   \\  =  > 57\degree + (3x + 6)\degree = 180\degree - 90\degree \\ \\  =  > 57\degree + (3x + 6)\degree = 90\degree

Two Angles are Complementary when they add up to 90° (a Right Angle).

=  > 57 \degree + (3x + 6) \degree = 90 \degree \\  \\  =  > 57 \degree + 3x \degree + 6 \degree = 90 \degree \\  \\  =  > 63 \degree + 3x \degree = 90 \degree \\  \\  =  > 3x \degree = 90 \degree - 63 \degree \\  \\  =  > 3x \degree = 27 \degree \\ \\ = > x\degree = \frac{27}{3}\degree \\ \\ = > x\degree = 9\degree

KatRina [158]2 years ago
5 0

57+3x+6=90degree

60+3x=90

3x=90-60

3x=30

x=30/3

x=10

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I do not understand how I find answers on here
Volgvan
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One solution to the problem below is 4.<br> What is the other solution?<br> y² - 16 = 0
ratelena [41]

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The 2 answers are 4 and -4

Step-by-step explanation:

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3 years ago
The volume V of an ice cream cone is given by V = 2 3 πR3 + 1 3 πR2h where R is the common radius of the spherical cap and the c
Nuetrik [128]

Answer:

The change in volume is estimated to be 17.20 \rm{in^3}

Step-by-step explanation:

The linearization or linear approximation of a function f(x) is given by:

f(x_0+dx) \approx f(x_0) + df(x)|_{x_0} where df is the total differential of the function evaluated in the given point.

For the given function, the linearization is:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh

Taking R_0=1.5 inches and h=3 inches and evaluating the partial derivatives we obtain:

V(R_0+dR, h_0+dh) = V(R_0, h_0) + \frac{\partial V(R_0, h_0)}{\partial R}dR + \frac{\partial V(R_0, h_0)}{\partial h}dh\\V(R, h) = V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh

substituting the values and taking dx=0.1 and dh=0.3 inches we have:

V(R_0+dR, h_0+dh) =V(R_0, h_0) + (\frac{2 h \pi r}{3}  + 2 \pi r^2)dR + (\frac{\pi r^2}{3} )dh\\V(1.5+0.1, 3+0.3) =V(1.5, 3) + (\frac{2 \cdot 3 \pi \cdot 1.5}{3}  + 2 \pi 1.5^2)\cdot 0.1 + (\frac{\pi 1.5^2}{3} )\cdot 0.3\\V(1.5+0.1, 3+0.3) = 17.2002\\\boxed{V(1.5+0.1, 3+0.3) \approx 17.20}

Therefore the change in volume is estimated to be 17.20 \rm{in^3}

4 0
3 years ago
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