Answer:
Side a = 88.67626
Side b = 57
Side c = 67.92995
Angle ∠A = 90° = 1.5708 rad = π/2
Angle ∠B = 40° = 0.69813 rad = 2/9π
Angle ∠C = 50° = 0.87266 rad = 5/18π
Area = 1,936.00371
Perimeter p = 213.60621
Semiperimeter s = 106.80311
Height ha = 43.66453
Height hb = 67.92995
Height hc = 57
Median ma = 44.33813
Median mb = 73.66633
Median mc = 66.35224
Inradius r = 18.12685
Circumradius R = 44.33813
Vertex coordinates: A[0, 0] B[67.92995, 0] C[0, 57]
Centroid: [22.64332, 19]
Inscribed Circle Center: [18.12685, 18.12685]
Circumscribed Circle Center: [33.96498, 28.5]
The pattern is mutiplying each time by 3 so the 6th figure would be 18 because 3×6=18
Answer:
789 m²
Step-by-step explanation:
Consider the cross section created by a vertical plane through the apex of the pyramid and bisecting opposite sides. The cross section is an isosceles triangle with base 20 m and height 17 m. One side of this triangle is the slant height of the face of the pyramid.
The side of the triangle above can be found using the Pythagorean theorem. A median from the apex of the triangle will divide it into two right triangles, each with a base of 10 m and a height of 17 m. Then the hypotenuse is ...
s² = (10 m)² +(17 m)² = 389 m²
s = √389 m ≈ 19.723 m . . . . . slant height of one triangular face
__
The area of one triangular face is ...
A = (1/2)sb
where s is the slant height above, and b is the 20 m base of the face of the pyramid. There are 4 of these faces, so the total area is ...
total lateral area = 4A = 4(1/2)sb = 2sb = 2(19.723 m)(20 m)
total lateral area ≈ 789 m²
Answer:
x=10
Step-by-step explanation:
set it up and solve
2x-1=x+9
2x=x+10
x=10
Graphically: graph your equations and look for the intersections (these are your answers).
Algebraically: set your equations into y = format (below) and plug your values into the quadratic formula.
y = ax^2 + bx + c
(example: y = 2x^2 + 5x + 6; a = 2, b = 5, c = 6)