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3 years ago

How do you write a linear equation given the slope and a point that

Mathematics

1 answer:

Serga [27]3 years ago

6 0

Answer:

point slope form

Step-by-step explanation:

hi! we can use point slope form:

y-y1=m(x-x1)

where m is the slope, x1 is the x-coordinate of the given point, and y1 is the y-coordinate of the given point.

example:

slope is 4

ordered pair is (2,3)

y-3=4(x-2)

y-3=4x-8

y=4x-5

hope this helps!

You might be interested in

Find m<1 and m<2<br> Help

ANTONII [103]

Answer:

m<1 = 45

m<2 = 135

Step-by-step explanation:

135 is across from the 135 making m1 135 and 135 plus 45 equals 180, 180 is the total for the line the other 2 angles are on.

5 0

3 years ago

The roof on a shed is a square-based pyramid. if the base has a side length of 10 feet and the slant length of the root is 9.4 f

max2010maxim [7]

We know that

[the area of the root]=4*[area of one lateral triangle side]

area of one lateral triangle side=b*h/2
b=10 ft
h=9.4 ft
area of one lateral triangle side=10*9.4/2-----> 47 ft²

[the area of the root]=4*[47]-------> 188 ft²

the answer is
the area of the root is 188 ft²

3 0

4 years ago

Read 2 more answers

Marsha Green makes $9.19 per hour. Find her social security tax at the rate of 7.65% for a 40-hour work week.

ira [324]

Answer:

$28.12

Step-by-step explanation:

$9.19 x 40 = $367.60 x 7.65% = $28.12

5 0

4 years ago

Give a third degree polynomial that has zeros of 13, 5i, and −5i, and has a value of −680 when x=3. Write the polynomial in stan

Vikki [24]

Answer:

$\dfrac{17x^3-221x^2+425x-5525}{9}\\$

Step-by-step explanation:

hello

we need to find something like, a being real

$a(x-13)(x-5i)(x+5i)$

with a so that

$a(3-13)(3-5i)(3+5i)=-680\\\\a(-10)(3^2-(5i)^2)= -10(9+25)a=-360a=-680\\ a = \dfrac{680}{360}=\dfrac{17*40}{9*40}=\dfrac{17}{9}$

so the third degree polynomial that we are looking for is

$\dfrac{17}{9}(x-13)(x-5i)(x+5i)\\=\dfrac{17}{9}(x-13)(x^2+25)\\\\=\dfrac{17}{9}(x^3+25x-13x^2-13*25)\\\\\\=\dfrac{17}{9}(x^3-13x^2+25x-325)\\\\\\\\=\dfrac{17}{9}x^3-\dfrac{17*13}{9}x^2+\dfrac{17*25}{9}x-\dfrac{17*325}{9}\\=\dfrac{17}{9}x^3-\dfrac{221}{9}x^2+\dfrac{425}{9}x-\dfrac{5525}{9}\\$

hope this helps

3 0

4 years ago

If m∠WXY =160, what are m∠WXZ and m∠ZXY

Dominik [7]

Answer:

so it would be (7x-4)+(5x+8) = 160

x=13

4 0

3 years ago