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maxonik [38]
3 years ago
6

I will give brainliest to whoever helps me with this question. Also, if you could please explain to me how you solved it I would

appreciate it!

Mathematics
2 answers:
lesya [120]3 years ago
6 0

Answer:

20x3.14=62.8 62.8x10=628 Volume=628inches

Step-by-step explanation:

Plz give me brainlist

lina2011 [118]3 years ago
4 0

Answer:

3,140

Step-by-step explanation:

V=Bh

Pi(r^2)h

3.14 x 10^2 x 10

\ \

= 3.14 x 10 x 10 x 10

=3,140

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Write an equation of the line in slope-intercept form.<br><br><br><br> The equation is y= <br> .
aivan3 [116]

Answer:

y = x + 2

Step-by-step explanation:

     Slope-intercept form is y = mx + b where m is the slope and b is the y-intercept. Here, b is equal to 2 because the line crosses the y-axis at 2. THe slope is rise over run, or the change in y divided by the change in x. From the two points given, we get 3/3 which is equal to 1. 1x equals x, so this gives us "no slope." Putting it together gives us y = x + 2.

Have a nice day!

     I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

6 0
2 years ago
Which simplified expression is the difference of (0.5n+0.3) - (0.75n-0.45)
never [62]
The answer is B . your welcome
4 0
3 years ago
Will give Brainliest if u r good at math Plz help thank u :)
amid [387]
A) 5.23, 7.89, 10.22, 34.98, 51.02, 51.22 because the closer a decimal is to 99 the larger it is.

B) 128+34.98+51.02+51.22=265.22
265.22-5.23-10.22-7.89=241.88
She had $241.88 in her bank account

6 0
3 years ago
Two surveys were independently conducted to estimate a population mean, μ. denote the estimates and their standard errors by x1
lyudmila [28]

Hi there what you need is lagrange multipliers for constrained minimisation. It works like this,

V(X)=α2σ2X¯1+β2\sigma2X¯2

Now we want to minimise this subject to α+β=1 or α−β−1=0.

We proceed by writing a function of alpha and beta (the paramters you want to change to minimse the variance of X, but we also introduce another parameter that multiplies the sum to zero constraint. Thus we want to minimise

f(α,β,λ)=α2σ2X¯1+β2σ2X¯2+λ(\alpha−β−1).

We partially differentiate this function w.r.t each parameter and set each partial derivative equal to zero. This gives;

∂f∂α=2ασ2X¯1+λ=0

∂f∂β=2βσ2X¯2+λ=0

∂f∂λ=α+β−1=0

Setting the first two partial derivatives equal we get

α=βσ2X¯2σ2X¯1

Substituting 1−α into this expression for beta and re-arranging for alpha gives the result for alpha. Repeating the same steps but isolating beta gives the beta result.

Lagrange multipliers and constrained minimisation crop up often in stats problems. I hope this helps!And gosh that was a lot to type!xd

3 0
3 years ago
2 ÷ 2 × 2 ÷ 2 plz anwers for point
natima [27]
It equals 1 thanks for the potion
7 0
2 years ago
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