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hichkok12 [17]
2 years ago
12

2. Camilla sold 181 tickets for the school play. Student tickets cost $12 and adult

Mathematics
2 answers:
alekssr [168]2 years ago
8 0
She sold 5 tickets that night
aliya0001 [1]2 years ago
8 0

Answer:

Adult=84, student=97

Step-by-step explanation:

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Prime factorisation of 49, 56,42 plz answer
ra1l [238]
49=7²
56=2³*7
42=2*3*7
4 0
3 years ago
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Matt bought an iPod from the Apple Store for $350. If it's value will depreciate by $52 a year, how much should Matt sell his iP
Bogdan [553]
Decreasing by $52 every year, we need to subtract 52 for each year. 

350 is the original price. 
52x is the amount decreased by how many years

350 - 52(3) = ?
350-156 = 194

Answer: Matt should sell his iPod for $194 in 3 years
6 0
3 years ago
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Can a triangle have sides with the given​ lengths? Explain.
Nookie1986 [14]
No because when you add any 2 sides the answer has to be bigger than the 3rd side

ex: 2+7=9
9 is too small, so the tips of the side that is 2ft would not touch the side that is 7ft
4 0
3 years ago
Jenise throws a ball 75 times and hits the target 41 times. What is the experimental probability that she will hit the target? S
Nutka1998 [239]

Answer:

Step-by-step explanation:

Probability is the ratio of the required outcome to the total possible outcome

Total outcome = 75

Number of times target was hit (expected outcome) = 41

Pr(she will hit target)= 41/75

Next is to state in percent and u do that by multiplying the resulting fraction by 100

41/75 i n percent.

41/75×100

= 4100/75

= 54.67%

Hence the answer in percentage is 54.67%

7 0
2 years ago
a line whose perpendicular distance from the origin is 4 units and the slope of perpendicular is 2÷3. Find the equation of the l
GrogVix [38]

Answer:

\huge\boxed{y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{2}{3}x+\dfrac{4\sqrt{13}}{3}}

Step-by-step explanation:

The equation of a line:

y=mx+b

We have

m=\dfrac{2}{3}

substitute:

y=\dfrac{2}{3}x+b

The formula of a distance between a point and a line:

General form of a line:

Ax+By+C=0

Point:

(x_0,\ y_0)

Distance:

d=\dfrac{|Ax_0+By_0+C|}{\sqrt{A^2+b^2}}

Convert the equation:

y=\dfrac{2}{3}x+b     |<em>subtract y from both sides</em>

\dfrac{2}{3}x-y+b=0    |<em>multiply both sides by 3</em>

2x-3y+3b=0\to A=2,\ B=-3,\ C=3b

Coordinates of the point:

(0,\ 0)\to x_0=0,\ y_0=0

substitute:

d=4

4=\dfrac{|2\cdot0+(-3)\cdot0+3b|}{\sqrt{2^2+(-3)^2}}\\\\4=\dfrac{|3b|}{\sqrt{4+9}}

4=\dfrac{|3b|}{\sqrt{13}}\qquad|    |<em>multiply both sides by \sqrt{13}</em>

4\sqrt{13}=|3b|\iff3b=-4\sqrt{13}\ \vee\ 3b=4\sqrt{13}   |<em>divide both  sides by 3</em>

b=-\dfrac{4\sqrt{13}}{3}\ \vee\ b=\dfrac{4\sqrt{13}}{3}

Finally:

y=\dfrac{2}{3}x-\dfrac{4\sqrt{13}}{3}\ \vee\ y=\dfrac{4\sqrt{13}}{3}

4 0
2 years ago
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