Write the first 4 terms for this sequence t(n)=4.5n-8

2 answers:

6 0

Evaluate t(1),t(2),t(3),t(4)

t(1)=4.5(1)-8=4.5-8=-3.6
t(2)=4.5(2)-8=9-8=1
t(3)=4.5(3)-8=13.5-8=5.5
t(4)=4.5(4)-8=18-8=10

the first 4 terms are
-3.6,1,5.5, 10

Anon25 [30]4 years ago

3 0

Simplifying t(n) = 4.5n + -8 Multiply t * n nt = 4.5n + -8 Reorder the terms: nt = -8 + 4.5n Solving nt = -8 + 4.5n Solving for variable 'n'. Move all terms containing n to the left, all other terms to the right. Add '-4.5n' to each side of the equation. -4.5n + nt = -8 + 4.5n + -4.5n Combine like terms: 4.5n + -4.5n = 0.0 -4.5n + nt = -8 + 0.0 -4.5n + nt = -8 Reorder the terms: 8 + -4.5n + nt = -8 + 8 Combine like terms: -8 + 8 = 0 8 + -4.5n + nt = 0 The solution to this equation could not be determined.

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denis23 [38]

Hello!

Answer:

1. =-6

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Explanation: This question's it's about the order of operations. It stands for p-parenthesis, e-exponents, m-multiply, d-divide, a-add, and s-subtract. It can also go left to right. (PEMDAS)

1. -4(3-1)+2

Do parenthesis first.

$(3-1)=2$