Step-by-step explanation:
Price increase = $80 - $52 = $28.
Percentage increase = ($28/$52) * 100%
= 53.8% = 54%. (nearest percent)
Alright! We know that the total number of students is 100%. So, if 65% of the students brought a hot lunch, in order to find how many students brought a packed lunch you subtract it from 100%:
[100 - 65] = 35
So 35% of the students brought a packed lunch. Now, in order to find the fraction of students you simply put 35% of students over the total percent of students (100%)"
[35/100]
Then you simply:
[35/100] ⇒ [7/20]
The answer is 7/20ths of the students brought a packed lunch.
More:
Decimal form - .35
Percentage form - 35%
Answer: (0.205905, 0.242095)
Step-by-step explanation:
We know that the confidence interval for population proportion is given by :-
, where 
= sample proportion
n= sample size
Let p be the proportion of complaints of identity theft .
As per given , we have
n= 1432
By standard normal table , z* = 1.645 for 90% confidence level.
Now , 90% confidence interval for p will be :
Hence, required confidence interval = (0.205905, 0.242095)
C is the answer to this question
Answer: combining like terms
Step-by-step explanation:
