48 because that's what you get following your equation in PEMDAS order :)
Answer:
Yes, P(A) = P(A|B)
Step-by-step explanation:
The context of the question is incomplete but I've assumed logically what it might be;
Whether a traveller flies or doesn't fly to their destination is unrelated to whether they home share or not;
Therefore, they are independent;
Independent events are events where the outcome of one event has no effect on the probabilities of the outcomes from a second event;
This can be represented mathematically as: P(A) = P(A|B);
The corollary of this is P(B) = P(B|A);
A common example easily understood would be if you flip a coin, there is a 50% chance of heads and 50% chance of tails;
If I flip and gets a heads first, the probability of getting a heads or tails on the second, third or tenth flip is going to be unchanged, i.e. 50% chance of heads and 50% chance of tails
She would pay $4.06 in taxes the total would be $62.06
Answer:
A.
(3, -8)
Step-by-step explanation:
4/10,5/8,38/100
2 10,8,100
2 5, 4, 50
2 5, 2, 25
5 5, 1, 25
5 1, 1, 5
1, 1, 1
2*2*2*5*5=200
4/10=4*200110
=80
5/8=5*200/8
=125
38/100=38*200/100
=76
76,80,125
The answer is 38%,0.4,5/8
