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Norma-Jean [14]
4 years ago
3

A borrower pays 18% interest per year on the

Mathematics
1 answer:
marin [14]4 years ago
4 0

Answer:

The interest will the borrower pay on is Rs. 1,026 ⇒ answer b

Step-by-step explanation:

* Lets explain how to solve the problem

- A borrower pays 18% interest per year on the first Rs. 600 he borrows

- He pays 17% per year on the  loan on the part of the loan in excess

 of Rs. 600

- We need to find the interest he will pay on the loan of 6000 for a year

∵ The lone is Rs. 6000 for 1 year

∵ He pays 18% interest for the first Rs. 600

∵ I = Prt , where I is the interest , P is the loan amount , r is the rate

  of interest in decimal t is the time

∵ P = 600

∵ r = 18/100 = 0.18

∵ t = 1

∴ I = 600 × 0.18 × 1 = 108

* <em>The interest for the first Rs. 600 is Rs. 108</em>

- The loan is Rs. 6000 , we calculated the interest for the first

 Rs. 600, then we want to calculate the interest for the rest of

 the loan at rate 17% per year

∵ The rest of the loan = 6000 - 600 = 5400

∵ P = 5400

∵ r = 17/100 = 0.17

∵ t = 1

∴ I = 5400 × 0.17 × 1 = 918

* <em>The interest for the rest of the loan is Rs. 918</em>

- The total interest is the sum of the two interest above

∵ The interest of Rs. 600 is Rs. 108

∵ The interest of the rest of the loan is Rs. 918

∴ The total interest = 918 + 108 = 1026

* <em>The interest will the borrower pay on is Rs. 1,026</em>

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==================================================

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