Answer:
For 32 bits Instruction Format:
OPCODE DR SR1 SR2 Unused bits
a) Minimum number of bits required to represent the OPCODE = 3 bits
There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.
Ceil (log2 (8)) = 3
b) Minimum number of bits For Destination Register(DR) = 4 bits
There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.
Ceil (log2 (10)) = 4
c) Maximum number of UNUSED bits in Instruction encoding = 17 bits
Total number of bits used = bits used for registers + bits used for OPCODE
= 12 + 3 = 15
Total number of bits for instruction format = 32
Maximum No. of Unused bits = 32 – 15 = 17 bits
OPCODE DR SR1 SR2 Unused bits
3 bits 4 bits 4 bits 4 bits 17 bits
A spreadsheet function that indicates the average of a group of numbers in a range.
False. The more people you have the more likely you will have true conclusions...
Answer:
divide it into smaller pieces
Explanation:
Usually, the main reason a programmer does not understand a problem fully is that there is too much information. The best way to try and fully understand a problem is to divide it into smaller pieces. Start off by answering the question what is the expected output for an input. Then divide each individual issue within the problem. This will allow you as a programmer/developer to create an individual solution for each individual issue within the problem and then test to make sure that the input gives the correct output.