Answer:
See the proof below
Step-by-step explanation:
Let the line AB be a straight line on the parallelogram.
A dissection of the line (using the perpendicular line X) gives:
AY ≅ BX
Another way will be using the angles.
The angles are equal - vertically opposite angles
Hence the line AY ≅ BX (Proved)
The confidence interval formula is computed by:
Xbar ± Z s/ sqrt (n)
Where:
Xbar is the mean
Z is the z value
S is the standard deviation
N is the number of samples
So our given are:
90% confidence interval with a z value of 1.645
Sample size 40, 45
Mean 180, 179
Standard deviation 2, 4
So plugging that information in the data will give us a
confidence interval:
For 1:
Xbar ± Z s/ sqrt (n)
= 180 ± 1.645 (2 / sqrt (40))
= 180 ± 1.645 (0.316227766)
= 180 ± 0.520194675
= 179.48, 180.52
For 2:
Xbar ± Z s/ sqrt (n)
= 179 ± 1.645 (4 / sqrt (45))
<span>= 179 ± 1.645 (0.596284794)</span>
therefore, the answer is letter b
Answer: The required value is

Step-by-step explanation: The given functions are:

We are given to find the value of 
We know that, if s(x) and t(x) are any two functions of a variable x, then we have

Therefore, we have

Thus, the required value is

D. X = 8 , Y = 6
3x - 14 = x + 23x - x = 2 + 142x = 162x / 2 = 16/2x = 8
To check: 3x - 14 = x + 2 ; 3(8) - 14 = 8 + 2 ; 24 - 14 = 10 ; 10 = 10
4y - 7 = y + 114y - y = 11 + 73y = 183y / 3 = 18 / 3y = 6
To check: 4y - 7 = y + 11 ; 4(6) - 7 = 6 + 11 ; 24 - 7 = 17 ; 17 = 17
hopes it helps:)
The movies of 120 min or less than 120 mins are 100
Further explanation:
A histogram is a visual representation of data.
In the given histogram we can see that
5 movies are 0 to 30 minutes, 10 movies are 31 to 60 minutes, 30 movies are 61 to 90 minutes, 55 movies are 91 to 120 minutes, and 15 movies are over 120 minutes.
In order to find the number of movies which are 120 minutes long or less than 120 minutes we will add up all the number of movies with 120 length and less than that
So,

The movies of 120 min or less than 120 mins are 100
Keywords: Histogram, reading histograms
Learn more about histograms at:
#LearnwithBrainly