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pickupchik [31]
3 years ago
10

HELP MATH ONE MORE AFTER THIS

Mathematics
2 answers:
Grace [21]3 years ago
6 0

Step-by-step explanation:

<u>Step 1:  Find the hypotenuse</u>

a^2+b^2 =c^2

(7)^2 + (3)^2 = c^2

49 + 9 = c^2

58 = c^2

Square area = a^2

a^2 = c^2

Area = 58

Answer: 58 units squared

Lady_Fox [76]3 years ago
5 0

Answer:

58 units squared

Step-by-step explanation:

We want to find the area of the square. To do so, we need to find the hypotenuse of the right triangle because this coincides with the side length of the square.

We use the Pythagorean Theorem, which states that for a right triangle with legs a and b and hypotenuse c:

a^2 + b^2 = c^2

Here, a = 7 and b = 3, so:

7^2 + 3^2 = c^2

c^2 = 49 + 9 = 58

Now, the area of a square is: A = s^2, where s is the side length. Well, c is the side length, and we've already found what c^2 is (it's 58), so that means the area of the square is 58 units squared.

Thus, the answer is 58 units squared.

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-4x + 2(5x - 6) = 6(x - 2)
Ugo [173]

Answer:

Sorry but this equation gives me 6x-12=6x-12

Step-by-step explanation:

Hope u don't mind me asking but have u tried it out yet and what did you get???

Is that a negative b4 4x??

8 0
3 years ago
Find the value of x below
ehidna [41]

Answer:

x=58 degrees

Step-by-step explanation:

The angle DB is equal to 90 degrees, so if you subtract 32 from 90 you get x, which is 58.

3 0
4 years ago
What is the quotient and remainder of 773 divided by 8
IRISSAK [1]
96 with a remainder of 5.
3 0
4 years ago
4-Fui al supermercado y había un descuento del 15% en el total de la compra, si pagaba en efectivo. Gasté $ 2.400. ¿Qué cantidad
Grace [21]

Answer:

$2.040

Step-by-step explanation:

Para calcular la cantidad que fue abonada en realidad, debes encontrar el valor del descuento calculando el 15% del valor total de la compra y este resultado se debe restar del total:

$2.400*15%= $360

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6 0
3 years ago
(3x+2)∧2=9 how do i solve this in the square root property
Irina18 [472]
(3x+2)^2=9 \\\\9x^2+12x+4-9=0\\\\9x^2+12x-5=0\\\\a=9,\ \ b=12, \ \ c=-5

x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a}=\frac{-12-\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12-\sqrt{144+180}}{18}=\\\\=\frac{-12-\sqrt{324}}{18}=\frac{-12-18}{18}=\frac{-30}{18}=-\frac{5}{3}\\\\x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a}=\frac{-12+\sqrt{12^2-4 \cdot9 \cdot (-5)}}{2 \cdot 9}=\frac{-12+18}{18}=\frac{6}{18}=\frac{1}{3} \\\\Answer: \ x=-\frac{5}{3}\ \ and \ \ x=\frac{1}{3}
 

6 0
3 years ago
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