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pickupchik [31]
4 years ago
10

HELP MATH ONE MORE AFTER THIS

Mathematics
2 answers:
Grace [21]4 years ago
6 0

Step-by-step explanation:

<u>Step 1:  Find the hypotenuse</u>

a^2+b^2 =c^2

(7)^2 + (3)^2 = c^2

49 + 9 = c^2

58 = c^2

Square area = a^2

a^2 = c^2

Area = 58

Answer: 58 units squared

Lady_Fox [76]4 years ago
5 0

Answer:

58 units squared

Step-by-step explanation:

We want to find the area of the square. To do so, we need to find the hypotenuse of the right triangle because this coincides with the side length of the square.

We use the Pythagorean Theorem, which states that for a right triangle with legs a and b and hypotenuse c:

a^2 + b^2 = c^2

Here, a = 7 and b = 3, so:

7^2 + 3^2 = c^2

c^2 = 49 + 9 = 58

Now, the area of a square is: A = s^2, where s is the side length. Well, c is the side length, and we've already found what c^2 is (it's 58), so that means the area of the square is 58 units squared.

Thus, the answer is 58 units squared.

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Vinil7 [7]

the correct answer choice is B.

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3 years ago
True or False?In Exercise,determine whether the statement is true or false given that f(x) = In x.if it is false,explain why or
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Answer:

False

Step-by-step explanation:

This is false. We can disprove this by plugging in the number into the function f(x) = lnx

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3 years ago
What is the value of x, y, and z?
deff fn [24]

Answer:  x = 34º,  y = 146º,  z = 146º

Step-by-step explanation:

Adding the angles inside a triangle gives you 180º. So

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7 0
3 years ago
Use the list of five irrational below to answer the questions
ExtremeBDS [4]

Answer:

  \text{A.}\ \sqrt{2}\times\sqrt{18}\\\\\text{B.}\ \sqrt{2}\times\sqrt{6}

Step-by-step explanation:

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  \text{1.}\ \sqrt{2}\times\sqrt{18}=\sqrt{36}=6\\\\\text{2.}\ \sqrt{6}\times\sqrt{24}=\sqrt{144}=12

__

B: The root will be irrational if the product of the numbers under the radicals is not a perfect square. For this part, there are many choices.

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6 0
4 years ago
9q − 6q − 2q = 18 solve for q
Yuri [45]
9q-8q=18
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3 years ago
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