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madam [21]
3 years ago
10

Find the sum of the first 12 terms of the sequence. show all work for full credit. 1,-4,-9,-14,...

Mathematics
1 answer:
alexgriva [62]3 years ago
4 0

Let's find the rule where.

1-(-4)=5

-4-(-9)=5

It looks like we are subtracting 5 from the previous number. Since we know the rule, let's write out all.

1, -4, -9, -14, -19, -24, -29, -34, -39, -44, -49, -54; let's add them.

-318 is the sum

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How to answer number 10
Ipatiy [6.2K]

You were on the right track.

(17/4)*(11/4)*(3/1)

first multiply the numerators

17*11*3 = 561

561 / ?

next multiply the denominators

4*4*1 = 16

561 / 16 = 35.0625 = 35 1/16

5 0
3 years ago
If H^1 (x) is the inverse of H (x), what is the value of H^-1 (H (x))?
anyanavicka [17]
Note as a fact:

H⁻¹(H(x)) = x

Option C.
3 0
3 years ago
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A few more need to get done ty
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Answer:

YES

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YES

NO

Step-by-step explanation:

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3 0
3 years ago
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Can someone help me with this question.
koban [17]
We will set each parentheses equal to 0
x - 4 = 0
x = 4
-5x + 1 = 0
x = 1/5
The lesser value will be 1/5
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7 0
3 years ago
A metalworker has a metal alloy that is 30% copper and another alloy that is 65% copper. How many kilograms of each alloy should
LenKa [72]

Step-by-step explanation:

If x is the mass of 30% copper alloy, and y is the mass of 65% copper alloy, then:

x + y = 80

0.30x + 0.65y = 0.51(80)

Solving the system of equations using substitution:

0.30x + 0.65(80 − x) = 0.51(80)

0.30x + 52 − 0.65x = 40.8

11.2 = 0.35x

x = 32

y = 80 − x

y = 48

The metalworker needs 32 kg of 30% copper alloy and 48 kg of 65% copper alloy.

7 0
4 years ago
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