Answer:
Yes
Step-by-step explanation:
Answer:
19
Step-by-step explanation:
Answer:
Option A and C have rotational symmetry.
Step-by-step explanation:
The graph of odd functions have rotational symmetry about its origin.
Here the first graph is a graph of f(x)=
which is an odd function bearing an exponent of 3.
A function is "odd" when we plug in any negative value in
then it gives negative of
.
And we also know that when a graph is mirroring about the y-axis then it is an even functions.
For even functions we have reflection symmetry rather than rotational symmetry.
The second graph is a graph of
which is an even function as we can see that its graph is mirroring about the y-axis.
The third graph is a graph of an ellipse which is possessing rotational symmetry.
The order of symmetry of an ellipse is generally 2.
Order of symmetry:
The order of rotational symmetry of an object is how many times that object is rotated and fits on to itself during a full rotation of 360 degrees.
So graph A and C have rotational symmetry.
Answer:B
Step-by-step explanation:
9. x + (y - 3 - 4x + 2( 3x - (-y - 1) + 2y) - 3x)
= x + (y - 3 - 4x + 2 (3x + y - 1) + 2y - 3x)
= x + (y - 3 - 4x + 6x + 2y - 2 + 2y - 3x)
= (x - 4x + 6x - 3x) + (y + 2y + 2y) - (3+2)
= 0 + 5y - 5
= 5y - 5 (or simplified as 5(y-1)
10. 6 + (-a -3(b + 6(a - b)+4a) - 2b)
= 6 + (-a - 3(b + 6a - 6b + 4a) -2b)
= 6 + (-a - 3b + 18a - 18b + 12a - 2b)
= 6 + (-a + 18a + 12a) + (-3b - 18b - 2b)
= 6 + 29a - 23b
Lmk if it's wrong, I'll try to edit it.