The answer should be 25.64$
You multiple that by 8% and then what you get out of it you add on to what you got as the total .
Answer:
x + 5
Step-by-step explanation:
Therefore, the answer is x + 5.
Have a lovely rest of your day/night, and good luck with your assignments! ♡
Answer:
Step-by-step explanation:
Given that
sample size n = 55: x bar = 654.16 and s = sample sd = 162.34
Std error = 162.34/sqrt 55 = 21.889
For 95% CI we can use t critical value as population std dev is not known.
df = 54
t critical = 2.004
Margin of error = 2.004 *21.889 = 43.866
Confidence interval lower bound = 654.16-43.866 =610.294
Upper bound = 654.16+43.866=698.026
Confidence interval rounded off at 95% = (610.29, 698.23)
Y = -x^2 + x + 2
y = -x + 3
-x + 3 = -x^2 + x + 2
x^2 - x - 2 - x + 3 = 0
x^2 -2x + 1 = 0
(x - 1)(x - 1) = 0
x - 1 = 0 y = -x + 3
x = 1 y = -1 + 3
y = 2
solutions are : (1,2) , (1,2)
There were 40 tourist class passengers and 12 first class passengers.
Explanation:
Let the number of passengers who booked for tourist class be
=
x
Then, number of passengers who booked for first class
=
52
−
x
According to question,
Total money paid = $25(tourist class)+$30(first class)
$
1360
=
$
25
(
x
)
+
$
30
(
52
−
x
)
1360
=
25
x
+
1560
−
30
x
1360
−
1560
=
25
x
−
30
x
−
200
=
−
5
x
x
=
−
200
−
5
x
=
40
So, there were 40 tourist class passengers.
Now first class passengers
=
52
−
x
=
52
−
40
=
12
∴
There were 40 tourist class passengers and 12 first class passengers.
As a check
Total money paid = $25(tourist class)+$30(first class)
R
H
S
=
$
25
(
40
)
+
$
30
(
12
)
$
1000
+
$
360
=
$
1360
L
H
S
=
$
1360
Hence verified.
