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Tanya [424]
3 years ago
7

What is an equation of a line, in point-slope form, that passes through (1,-7) and has a slope of -2/3?

Mathematics
1 answer:
Brut [27]3 years ago
3 0

Answer: y + 7 = -2/3 (x - 1 )

Step-by-step explanation:

The equation of a line in point - slope form is given as :

y-y_{1} = m(x-x_{1} )

Where m is the slope and (x_{1} , y_{1}) is the given point

substituting the values into the formula , we have:

y - (-7) = -2/3 ( x - 1)

y + 7 = -2/3(x - 1 )

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Step-by-step explanation:

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Liono4ka [1.6K]

Answer:

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7 0
2 years ago
The area of the city of Vancouver is 115 km^2. if the shape of Vancouver is approximately a square, how wide is the city of Vanc
Dmitry [639]

Answer:

The wide of the city is 10.7km

Step-by-step explanation:

To solve this we first have to know the formula to calculate the area of ​​a square

a = area = 115 km²

s = side

a = s * s

now we replace with the known values

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10.724km = s

Round to the nearest tenth

s = 10.724km = 10.7km

The wide of the city is 10.7km

5 0
3 years ago
TV=3x-24 and VX=2x+1. What is the value of VX?<br> 1. 25<br> 2. 99<br> 3. 5<br> 4. 51
Maslowich
ΔTXV is an <span>isosceles triangle because ∡T = ∡X therefore TV = VX.

3x - 24 = 2x + 1    |subtract 2x from both sides

x - 24 = 1    |add 24 to both sides

x = 25
</span>
7 0
3 years ago
Read 2 more answers
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