The numerical sum of the degree measures of m ∠DEA and m ∠AEF and m ∠DEF is 360°; The numerical measures of the angles is,
m ∠DEA = 56°
m ∠AEF = 158°
m ∠DEF = 146°
Based on the given data,
m ∠DEA= x + 30,
m ∠AEF= x + 132, and
m ∠DEF= 146 degrees
If the sum of two linear angles is 360° then, they are known as supplementary angles.
∠A + ∠B + ∠C = 360°, (∠A and ∠B and ∠C are linear angles.)
So,
We can write,
m ∠AEF + m ∠DEA + m ∠DEF = 360°
( x + 132) + (x + 30) + 146 = 360°
x + 30 + x + 132 + 146 = 360°
2x + 308 = 360°
2x = 360° - 308
x = 52/2
x =26
Now, we will substitute the value of x = 26° in the ∠DEA and ∠AEF, hence we get:
m ∠DEA = x + 30
m ∠DEA = 26 + 30
m ∠DEA = 56 degrees
Also,
m ∠AEF = x + 132
m ∠AEF = 26 + 132
m ∠AEF = 158
Hence,
m ∠DEA + m ∠AEF + m ∠DEF = 360°
56 + 158 + 146 = 360°
360° = 360°
Therefore,
Therefore, the numerical sum of the degree measures of m ∠DEA and m ∠AEF and m ∠DEF is 360°; The numerical measures of the angles is,
m ∠DEA = 56°
m ∠AEF = 158°
m ∠DEF = 146°
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Answer:
it would be something along the lines of. 5+25d =c
A tangent is a line that touches a circle only at one point
With the 3 colors - red=1, yellow=2 and green=5 - adding up to 8, that is one quarter the total of 32. Multiply each by 4 and you'll have - 4:8:20.
Given that <span>DG, EG, and FG are perpendicular bisectors of the sides of △ABC, this means that the point of intersection, G, is the circumcenter of the triangle and hence A</span><span>G, BG, and CG are equal.
Given that </span><span>DG = 5 cm and BD = 12 cm, then
Since AG = BG = CG, therefore, CG = 13 cm.</span>
