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Butoxors [25]
3 years ago
14

Rank the following factors in order from those that have the most effect on your credit score to those that have the least effec

t
on your credit score.
1. Amount of money owed
II. Payment history
III. Credit history length
a. I, II, III
b. II, I, III
C. II, III, 1
d. III, II,
Please select the best answer from the choices provided
O A
OB
Mathematics
1 answer:
Anvisha [2.4K]3 years ago
5 0
Lll Credit history length , 1 Amount is money owed, ll payment history
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(1A) At a movie theatre, the child ticket price is
marta [7]

Answer:I am pretty sure it is B obv that is the only one that makes enough sense (x+3.50)x65 (x)41 and the only one that makes sense to me is B!

Step-by-step explanation:

8 0
3 years ago
A glacier that was 1,076 meters thick changed in thickness at an average rate of -22.7 meters per year for 7 years.
sleet_krkn [62]
1,076 (the original thickness) - 22.7 meters (loss per year) * 7 (lost 22.7 meters per year for seven years, so multiply the loss per year by the amount of years) = 917.1 (the size after 7 years)

A.K.A  1,076 - 22.7 * 7 = 917.1
4 0
3 years ago
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Math question please show work for brainliest :)
VashaNatasha [74]

https://www.tiger-algebra.com/drill/3%7Cx-1%7C%3E=12/



Sources tiger algebra.com

5 0
3 years ago
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How to solve an expression with variables in the exponents?
gtnhenbr [62]

Answer:

  use logarithms

Step-by-step explanation:

Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.

__

You will note that this approach works well enough for ...

  a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents

  (x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs

but doesn't do anything to help you solve ...

  x +3 = b^(x -6)

There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.

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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.

In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.

8 0
3 years ago
What is the product of 3+2i and 3-2i?
Cloud [144]

Step-by-step explanation:

(3 + 2i)(3  -  2i) \\  \\  =  {3}^{2}  -  {(2i)}^{2}  \\  \\  = 9 - 4 {i}^{2}  \\  \\  = 9 - 4( - 1).. ( \because \:  {i}^{2} =  - 1)  \\  \\  = 9 + 4 \\  \\  = 13 \\  \\  \therefore \: (3 + 2i)(3  -  2i) = 13

6 0
3 years ago
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