Jason has one third of a gallon of milk.
2 answers:
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Let h be hamburgers and c be cheeseburgers.
We know that
We also know that
This gives us a system of equations we can solve. My preferred method to solve systems is substitution, where we solve one equation for one of the variables, then substitute that solution in the other equation, reducing it to a single variable equation. One of the equations already equals h, so we can go straight into the sub part.
Finally, we go back to the other equation and solve for h.
So, total there were 253 cheeseburgers sold, and 325 hamburgers sold.
We know that
We also know that
This gives us a system of equations we can solve. My preferred method to solve systems is substitution, where we solve one equation for one of the variables, then substitute that solution in the other equation, reducing it to a single variable equation. One of the equations already equals h, so we can go straight into the sub part.
Finally, we go back to the other equation and solve for h.
So, total there were 253 cheeseburgers sold, and 325 hamburgers sold.