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marysya [2.9K]
4 years ago
7

My homework is Identify the terms, like terms, coefficients, and constants in each expression and I need the answers to n+5n, 12

c- c, -4j-1-4j+6 I need answers to theses problems plz help me
Mathematics
1 answer:
AysviL [449]4 years ago
7 0

Step-by-step explanation:

A term is a number, a variable, or a constant multiplied by a variable or variables.

Like terms are terms that contain the same variables raised to the same power. Only the numerical coefficients are different.

A coefficient is a multiplicative factor in some term of a polynomial (expression).

Constant is a term in the algebraic expression that contain only number.

n + 5n = n + 5n + 0

terms: n, 5n

like terms: n, 5n

coefficients: 1, 5

constant: 0

simplified form: n + 5n = 6n

term: 6n

coefficient: 6

constant: 0

=======================

12c - c = 12c - c + 0

terms: 12c, -c

like terms: 12c, -c

coefficients: 12, -1

constant: 0

simplified form: 12c - c = 11c

term: 11c

coefficient: 11

constant: 0

========================

-4j - 1 - 4j + 6

terms: -4j, -1, -4j, 6

like terms: -4j, -4j and -1, 6

coefficients: -4, -4

constants: -1, 6

simplified form: -4j - 1 - 4j + 6 = (-4j - 4j) + (-1 + 6) = -8j + 5

term: -8j, 5

coefficient: -8

constant: 5

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What’s the equation in slope-intercept form?
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You can take any 2 points from the table and calculate the slope, as follows:
                     -2-(-4)        2
m = slope = ---------- = ------ = -1/5
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The slope-intercept form is    y = mx + b.  You already know m (which is -1/5), and have several points from which to choose to obtain x and y.  Let's use the given point (-2, -1).

Then    -1 = (-1/5)(-2) + b, or   -1 = 2/5 + b.  Solve for b.

-5 = 2 + 5b,  so  5b = -7, and b = -7/5.

The desired equation is     y = (-1/5)x - 7/5.
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A normal distribution has a mean of 15 and a standard deviation of 2. Find the value that corresponds to the 75th percentile.
kirill115 [55]

Answer:

The value that corresponds to the 75th percentile is 16.35.

Step-by-step explanation:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

A normal distribution has a mean of 15 and a standard deviation of 2.

This means that \mu = 15, \sigma = 2

Find the value that corresponds to the 75th percentile.

This is X when Z has a pvalue of 0.75. So X when Z = 0.675

Z = \frac{X - \mu}{\sigma}

0.675 = \frac{X - 15}{2}

X - 15 = 2*0.675

X = 2*0.675 + 15

X = 16.35

The value that corresponds to the 75th percentile is 16.35.

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