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belka [17]
4 years ago
12

If the sign for delta G is negative (spontaneous process) and the sign for delta S is positive (more disorder) for both dissolvi

ng processes, how could one be endothermic (positive delta H) and one be exothermic (negative delta H)
Chemistry
1 answer:
bogdanovich [222]4 years ago
3 0

Answer: From your question,

One could be exothermic which means that the final enthalpy will be less than the initial enthalpy. H= Hf-Hi(Hf<Hi).

In Endothermic reaction, the entropy is lowered by absorbing energy in the surronding. By so doing, the surronding losses energy and the reaction is not spontaneous.

H is positive and S (entropy) is positive.

Explanation:

Exothermic reaction is the reaction where heat is released In the surronding which lead to increase in the surronding Temperature.

Endothermic reaction is the reaction that absorb heat from the surronding and decrease the surronding Temperature.

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4 years ago
If the solubility of a gas is 10.5 g/L at 525 kPa pressure, what is the solubility of the gas when the pressure is 225 kPa? Show
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4.5 g/L.

Explanation:

  • To solve this problem, we must mention Henry's law.
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3 years ago
What are valence electrons and why are they so important in chemistry?
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valance electrons that reside in the outermost shell of an atom in the highest energy level. They are important to atoms because the fewer valence electrons that the atom holds, it becomes less stable.

I take honors chemistry I hope this helps.

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