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IRINA_888 [86]
3 years ago
14

How do you do empirical formula

Chemistry
1 answer:
mihalych1998 [28]3 years ago
7 0

Answer:

ez

Explanation:

Step 1: Obtain the mass of each element present in grams. Element % = mass in g = m.

Step 2: Determine the number of moles of each type of atom present. ...

Step 3: Divide the number of moles of each element by the smallest number of moles. ...

Step 4: Convert numbers to whole numbers.

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Joaquin's doctor tested Joaquin's reflexes by tapping his knee. The doctor
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Answer: Skeletal System

Explanation: Sense It's Sending up a signal up Joaquin's spinel cord It must be traveling threw his skeletal system

8 0
3 years ago
0.556 g of a solid white acid are dissolved in water and completely neutralized by the addition of 52.38 mL of 0.396 M NaOH. Cal
Veseljchak [2.6K]

Answer:

M_{acid}=26.804g/mol

Explanation:

Hello,

In this case, by knowing that the used NaOH equals in moles the acid (monoprotic) as shown below, during the titration:

n_{acid}=n_{NaOH}

By knowing the volume and the concentration of the NaOH, one obtains:

n_{acid}=0.05238L*0.396\frac{mol}{L}=0.0207mol

Thus, the molar mass of the acid is computed based on the previously computed moles and the given mass as follows:

M_{acid}=\frac{m_{acid}}{n_{acid}}=\frac{0.556g}{0.0207mol}=26.804g/mol

Best regards.

7 0
3 years ago
5. Hurricane winds are strongest and rain is heaviest in the part of a hurricane called the<br>​
Igoryamba

Answer:

In the center is the eye, with nearly clear skies, surrounded by the violent eyewall, with the strongest winds and very heavy rain.

Explanation:

3 0
3 years ago
Read 2 more answers
Which of the following is one way creativity can help scientists?
postnew [5]

Answer:

One way creativity is helpful to scientists is when they need to come up with a experiment or cure for something their imaginastion is very helpful. The reason for that is with creativity they could get answers much quicker!

Explanation:

7 0
3 years ago
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In a lab experiment 80.0 g of ammonia [NH3] and 120 g of oxygen are placed in a reaction vessel. At the end of the reaction 72.2
valentinak56 [21]

The percent yield of the reaction : 89.14%

<h3>Further explanation</h3>

Reaction of Ammonia and Oxygen in a lab :

<em>4 NH₃ (g) + 5 O₂ (g) ⇒ 4 NO(g)+ 6 H₂O(g)</em>

mass NH₃ = 80 g

mol NH₃ (MW=17 g/mol):

\dfrac{80}{17}=4.706

mass O₂ = 120 g

mol O₂(MW=32 g/mol) :

\tt \dfrac{120}{32}=3.75

Mol ratio of reactants(to find limiting reatants) :

\tt \dfrac{4.706}{4}\div \dfrac{3.75}{5}=1.1765\div 0.75\rightarrow O_2~limiting~reactant(smaller~ratio)

mol of H₂O based on O₂ as limiting reactants :

mol H₂O :

\tt \dfrac{6}{5}\times 3.75=4.5

mass H₂O :

4.5 x 18 g/mol = 81 g

The percent yield :

\tt \%yield=\dfrac{actual}{theoretical}\times 100\%\\\\\%yield=\dfrac{72.2}{81}\times 100\%=89.14\%

6 0
3 years ago
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