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umka21 [38]
3 years ago
11

Using the quadratic formula to solve x2+20=2x, what are the values of x​

Mathematics
2 answers:
spin [16.1K]3 years ago
8 0

Answer:

x = 1+ i\sqrt{19},1- i\sqrt{19}

Step-by-step explanation:

Given : x^2+20=2x

To Find: using the quadratic formula find x'

Solution:

Quadratic equation : ax^2+bx+c=0  ---1

Quadratic Formula : x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}

We are given :  x^2+20=2x

x^2-2x+20=0

On comparing with 1

a = 1

b = -2

c = 20

Substitute the values in the formula .

x = \frac{-(-2)\pm\sqrt{(-2)^2-4(1)(20)}}{2(1)}

x = \frac{2\pm\sqrt{4-80}}{2}

x = \frac{2\pm\sqrt{-76}}{2}

x = \frac{2\pm\sqrt{i^2 (2)(2)(19)}}{2}

x = \frac{2\pm 2i\sqrt{19}}{2}

x = 1\pm i\sqrt{19}

x = 1+ i\sqrt{19},1- i\sqrt{19}

Hence The values of x are  x = 1+ i\sqrt{19},1- i\sqrt{19}

alisha [4.7K]3 years ago
7 0
The answer to the question

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