Question

Using the quadratic formula to solve x2+20=2x, what are the values of x​

Answer 1

Answer:

$x = 1+ i\sqrt{19},1- i\sqrt{19}$

Step-by-step explanation:

Given : $x^2+20=2x$

To Find: using the quadratic formula find x'

Solution:

Quadratic equation : $ax^2+bx+c=0$  ---1

Quadratic Formula : $x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}$

We are given :  $x^2+20=2x$

$x^2-2x+20=0$

On comparing with 1

a = 1

b = -2

c = 20

Substitute the values in the formula .

$x = \frac{-(-2)\pm\sqrt{(-2)^2-4(1)(20)}}{2(1)}$

$x = \frac{2\pm\sqrt{4-80}}{2}$

$x = \frac{2\pm\sqrt{-76}}{2}$

$x = \frac{2\pm\sqrt{i^2 (2)(2)(19)}}{2}$

$x = \frac{2\pm 2i\sqrt{19}}{2}$

$x = 1\pm i\sqrt{19}$

$x = 1+ i\sqrt{19},1- i\sqrt{19}$

Hence The values of x are  $x = 1+ i\sqrt{19},1- i\sqrt{19}$

Answer 2

The answer to the question