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3 years ago

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Proponents of rational expectations theory argued that, in the most extreme case, if policymakers are credibly committed to redu

cing inflation and rational people understand that commitment and quickly lower their inflation expectations, the sacrifice ratio could be as small as A. 5. B. 4. C. 1. D. 0.

1 answer:

jarptica [38.1K]3 years ago

5 0

Answer:

The answer is zero or option D.

Step-by-step explanation:

Proponents of rational expectations theory argued that, in the most extreme case, if policymakers are credibly committed to reducing inflation and rational people understand that commitment, and quickly lower their inflation expectations, the sacrifice ratio could be as small as 0.

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A girls hair is 23 inches long how long and grows about half an inch every month how long will her hair be in 2 years

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Answer:

Step-by-step explanation:

1/2 multiplied by (12 multiplied by 2)

1/2 (24)

= 12 inches grown + 23 inches

= 35 inches long

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Lin counts 5 bacteria under a microscope. She counts them again each day for four days, and finds that the number of bacteria do

Liula [17]

Answer:

The population of bacteria can be expressed as a function of number of days.

Population = $5*2^{n-1}$ where n is the number of days since the beginning.

Step-by-step explanation:

Number of bacteria on the first day= $5 * 2^{0} = 5$

Number of bacteria on the second day = $5 * 2^{1} = 10$

Number of bacteria on the third day = $5*2^{2} = 20$

Number of bacteria on the fourth day = $5*2^{3} = 40$

As we can see , the number of bacteria on any given day is a function of the number of days n.

This expression can be expressed generally as $5*2^{n-1}$ where n is the number of days since the beginning.

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5/8 of 24 is equal to 15/7 of what number?

n200080 [17]

Answer:

fddsdfsd

Step-by-step explanation:

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3 years ago

Read 2 more answers

Blizzard [7]

Answer: h = 5

Step-by-step explanation:

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Let $f(x) = 2x^2 + 3x - 9,$ $g(x) = 5x + 11,$ and $h(x) = -3x^2 + 1.$ Find $f(x) - g(x) + h(x).$

Viefleur [7K]

QUESTION 1

Given that:

$f(x)=2x^2+3x-9$ ,

$g(x)=5x+11$ ,

and

$h(x)=-3x^2+1$

Then;

$f(x)-g(x)+h(x)=2x^2+3x-9-(5x+11)+(-3x^2+1)$

$f(x)-g(x)+h(x)=2x^2+3x-9-5x-11-3x^2+1$

Group similar terms;

$f(x)-g(x)+h(x)=2x^2-3x^2+3x-5x-11-9+1$

Simplify;

$f(x)-g(x)+h(x)=-x^2-2x-19$

QUESTION 2

Given that;

$f(x)=4x-7$ .

$g(x)=(x+1)^2$

and

$s(x)=f(x)+g(x)$

Substitute the functions;

$s(x)=4x-7+(x+1)^2$

Substitute x=3

$s(3)=4(3)-7+(3+1)^2$

$s(3)=12-7+(4)^2$

$s(3)=5+16$

$s(3)=21$

QUESTION 3

Given:

$f(x)=3x+2$

$g(x)=x^2-5x-1$

$f(g(x))=f(x^2-5x-1)$

This implies that;

$f(g(x))=3(x^2-5x-1)+2$

Expand the parenthesis;

$f(g(x))=3x^2-15x-3+2$

$f(g(x))=3x^2-15x-1$

QUESTION 4

The given function is;

$f(x)=3(x-6)^2+1$

Let

$y=3(x-6)^2+1$

$\Rightarrow y-1=3(x-6)^2$

$\Rightarrow \frac{y-1}{3}=(x-6)^2$

$\Rightarrow \sqrt{\frac{y-1}{3}}=x-6$

$\Rightarrow x=6+\sqrt{\frac{y-1}{3}}$

The range is:

$\frac{y-1}{3}\ge0$

$y-1\ge0$

$y\ge1$

The interval notation is;

$[1,+\infty)$

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3 years ago