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3 years ago

Which shape does Not stack? need help plzzzzzz its #2

Mathematics

2 answers:

Kisachek [45]3 years ago

8 0

The third one is the answer to this problem

cluponka [151]3 years ago

4 0

The shape that does not stack is the 3rd one the circle

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Susie is 5 feet and 6inches tall what would her height be in centimeters 1foot 12inches 1inch 2.54 centimeters

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2 years ago

At the zoo tje ratio of snakes to lizards is 3:2 A. If there were 10 lizards ,how many snakes would be there be? B.If there were

yawa3891 [41]

Answer:

Part A) $15\ snakes$

Part B) $6\ lizards$

Part C) The zoo would need to get four more lizards to maintain the same proportion

Part D) 12 snakes and 8 lizards

Step-by-step explanation:

Part A) If there were 10 lizards ,how many snakes would be there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

we have that

$y=10\ lizards$

substitute the value of y in the equation A

$\frac{x}{10}=\frac{3}{2}$

solve for x

$x=10(3)/2\\x=15\ snakes$

Part B) If there were 9 snakes ,how many lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

we have that

$x=9\ snakes$

substitute the value of x in the equation A

$\frac{9}{y}=\frac{3}{2}$

solve for y

$y=9(2)/3\\y=6\ lizards$

Part C) If the number of snakes in the zoo is increased by 6, how many more lizards would the zoo need to get to keep the same ratio?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$ ----> equation A

For $x=6\ snakes$

substitute the value of x in the equation A

$\frac{6}{y}=\frac{3}{2}$

solve for y

$y=6(2)/3\\y=4\ lizards$

therefore

The zoo would need to get four more lizards to maintain the same proportion

Part D) If the total number of snakes and lizards at the zoo was 20, how many snakes and lizards would there be?

Let

x ---> the number of snakes

y ---> the number of lizards

$\frac{x}{y}=\frac{3}{2}$

isolate the variable x

$x=1.5y$ ----> equation A

$x+y=20$ ----> equation B

solve the system by substitution

substitute equation A in equation B

$1.5y+y=20$

solve for y

$2.5y=20$

$y=8\ lizards$

Find the value of x

$x=1.5(8)=12\ snakes$

therefore

12 snakes and 8 lizards

8 0

3 years ago