Answer:
Step-by-step explanation:
Step-by-step explanation:
so, we need to find the smallest common multiple of 36 and 42.
that is the smallest number I can divide both by 36 and 42 without remain.
let's use the method of basic prime factors (we start with the smallest fitting prime number - 2 is a prime number too - and divide as often as possible, then continue with the next bigger prime number, until there is nothing left to divide) :
36 / 2 = 18
18 / 2 = 9
9 / 3 = 3
3 / 3 = 1 finished
therefore,
36 = 2×2×3×3
42 / 2 = 21
21 / 3 = 7
7 / 5 does not work
7 / 7 = 1 finished
therefore,
42 = 2×3×7
to find the smallest common multiple (SCM) we check the maximum length of each prime factor sequence.
and we see 2 times 2, 2 times 3 and 1 time 7.
so, the SCM = 2×2×3×3×7 = 252.
there is no smaller number that can be divided by both 36 and 42 without remain.
so, the rod must be at least 252 cm long to cut it into equally long pieces of either 36 cm (7 pieces) or 42 cm (6 pieces).
Answer:
-10 < x < -8
Step-by-step explanation:
Envision a number line. There is one whole number, -9, and and an infinite amount of fractions (rational numbers) and irrational numbers between -10 and -8.
X could be any of those values.
Firstly, write out as a number, using a few repeats of the decimal. If we multiply this number by 10 it will give a different number with the same digit recurring. When two digits recur multiply by 100 so that the recurring digits after the decimal point keep the same place value.
