Answer:
Required Probability = 0.1283 .
Step-by-step explanation:
We are given that at Meadow brook Hospital, the mean weight of babies born to full-term pregnancies is 7 lbs with a standard deviation of 14 oz.
Firstly, standard deviation in lbs = 14 ÷ 16 = 0.875 lbs.
Also, Birth weights of babies born to full-term pregnancies follow roughly a Normal distribution.
Let X = mean weight of the babies, so X ~ N(
)
The standard normal z distribution is given by;
Z = 
~ N(0,1)
where, X bar = sample mean weight
n = sample size = 4
Now, probability that the average weight of the four babies will be more than 7.5 lbs = P(X bar > 7.5 lbs)
P(X bar > 7.5) = P( > 
) = P(Z > 1.1428) = 0.1283 (using z% table)
Therefore, the probability that the average weight of the four babies will be more than 7.5 lbs is 0.1283 .
Answer:
0.677
Step-by-step explanation:Add up the values in the plan A column. There are 10+12+16 = 38 people who prefer plan A.
Add up the values in the "40-49" row to find that 16+8 = 24 people are ages 40 to 49.
We have 38+24-16 = 46 people who either prefer plan A, are aged 40-49, or fit both descriptions. I subtracted off 16 because those 16 people were counted twice when adding 38 and 24.
An alternative way to get this value of 46 is to add up everything that is in column1 or row 3 (or both). So that would get 10+12+16+8 = 46.
Now add up everything in the table to find out how many people were surveyed total. That would be 10+7+12+15+16+8 = 68 people overall.
The probability of someone liking plan A, or being age 40-49, or both is 46/68 = 0.6765 approximately. Rounding to 3 decimal places gives 0.677
Answer:
The answer should be 30x+120
Step-by-step explanation:
Answer:
2/3 is the constant of proportionality.
Answer:
Time:
Car > Truck > Boat.
Cost of produce:
Truck > Boat > Car
Profit
Car > Truck > Boat.
We know that a worker works 400 minutes each day, and the profit that each worker needs to generate is $35, let's find how each worker needs to spend their time.
Let's call T to the number of trucks he makes, C for cars and B for boats.
Then, if he works 400 minutes we have:
T*10 + C*12 + B*8 ≤ 400
this means that the time expended crafting the toys can be, at most, 400 minutes (here you use the inequality because the worker actually can be less effective than the max, maybe tacking a break or something like that)
The other equation is:
T*1 + C*1.5 + B*0.6 ≥ 35
Here we use the inequality because the profit needs to be at least 35$, none the less, the profit can be more than tath.
Notice that if we want to solve the system with for the equal signs, it is:
T*1 + C*1.5 + B*0.6 = 35
T*10 + C*12 + B*8 = 400
We have 3 variables and 2 equations, this means that there are more than one solution for this system.
