To locate emails with large attachments, go to your email and then choose the option of Choose File > Cleanup Tools > Mailbox Cleanup.
Here , one has to Log into their email account and open their inbox and then use the Search Mail bar and type Size to locate or they Set the Find items that are larger than to 9999 and then one has to click Find.
<h3>How do I find emails by attachment size?</h3>
This can also be done for messages that has a size equal to or bigger than 25.
One has to open their message and then they have to right-click on the attachment. You can choose Save As and save to the location of the choice you want.
Learn more about attachments from
brainly.com/question/978078
Answer:
well you can download some apps from the play store and it is easy for you to learn from there (interactive)
Given the way computers go about completing a linear search for an array of numbers, we can confirm that it would take about six steps to complete the search.
<h3>How do computers perform a linear search?</h3>
When given an array of numbers to search through the linear search method, the computer will follow a logical approach. It will begin at the leftmost number, in this case, the number 7, and then compare each number in the array to the number 52, one by one. When the number finally matches the parameter it is searching for, it will return the answer.
Since in this series of numbers, 52 is the fifth number, the computer will go through the 5 initial steps of comparing each number, and then complete the search with the sixth step which would be returning the index of 52.
Therefore, we can confirm that it would take about six steps for the computer to complete the search using a linear search.
To learn more about linear searches visit:
brainly.com/question/15178888?referrer=searchResults
Answer:
x1 = input("enter x value of first number: ")
y1 = input("enter y value of first number: ")
x2 = input("enter x value of second number: ")
y2 = input("enter y value of second number: ")
ans = (float(x2)-float(x1))**2 + (float(y2)-float(y1))**2
ans = pow(ans, 0.5)
print(ans)