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agasfer [191]
3 years ago
11

Given an array of n distinct integers,d = [d[0], d[1],.., d[n - 1]], and an integer threshold, t, how many (a,b,c) index triplet

s exist that satisfy both of the following conditions?
d[a] < d[b] < d[c]
d[a] + d[b] + d[c] ≤ t
Function Description
Complete the function triplets in the editor below. The function must return a long integer denoting the number of (a,b,c) triplets satisfying the given conditions:
t: an integer treshold
d[d[0],....d[n-1]] : an array of integers
Constraints
1 ≤ n ≤ 104
0 ≤ d[i] < 109
0 < t < 3 x109
#include ... /
Complete the triplets function below.
long triplets (long t, vector int> d) {
int main()
ofstream fout(getenv("OUTPUT_PATH"));
string t_temp;
getline (cin, t_temp);
long t = stol(ltrim(rtrim(t_temp)));
string d_count_temp;
getline (cin, d_count_temp);
int d_count = stoi(ltrim(rtrim(d_count_temp)));
vector int> d(d_count);
for (int i = 0; i < d_count; i++) {
string d_item_temp;
getline (cin, d_item_temp);
int d_item = stoi(ltrim(rtrim(d_item_temp)));
d[i] = d_item;
long res = triplets(t, d);
fout << res << "\n";
fout.close();
return 0;
string ltrim(const string &str) {
string s(str);
S.erase
Computers and Technology
1 answer:
Setler79 [48]3 years ago
4 0
I have a lot to say do not have to do this for the mnoth was the first day I was able to open and sign the new JTI documents and sign electronically sign up for additional support and electronically sign up for additional support and electronically sign documents electronically electronically sign the signature documents electronically sign up
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dolphi86 [110]

Answer:

The regular bottle holds 9 fluid ounces less than the family size bottle.

Explanation:

The family size bottle of sunscreen holds 12 fluid ounces

The regular bottle holds 75 percent less

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Since the regular bottle holds 75% less, it holds 9 fluid ounces fewer fluid than the family size bottle of sunscreen.

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A resistor bank is connected to a controller with conductor insulation rated 75 °C. The resistors are not used in conjunction wi
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Explanation:

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Multiply the FLC of the largest motor by 125%.

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Given an array as follows
slava [35]

Answer:

1) Method calcTotal:

  1. public static long calcTotal(long [][] arr2D){
  2.        long total = 0;
  3.        
  4.        for(int i = 0; i < arr2D.length; i++ )
  5.        {
  6.            for(int j = 0; j < arr2D[i].length; j++)
  7.            {
  8.                total = total + arr2D[i][j];
  9.            }
  10.        }
  11.        
  12.        return total;
  13.    }

Explanation:

Line 1: Define a public method <em>calcTotal</em> and this method accept a two-dimensional array

Line 2: Declare a variable, total, and initialize it with zero.

Line 4: An outer for-loop to iterate through every rows of the two-dimensional array

Line 6: An inner  for-loop to iterate though every columns within a particular row.

Line 8: Within the inner for-loop, use current row and column index, i and j, to repeatedly extract the value of each element in the array and add it to the variable total.

Line 12: Return the final total of all the element values as an output

Answer:

2) Method calcAverage:

  1. public static double calcAverage(long [][] arr2D){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            for(int j = 0; j < arr2D[i].length; j++)
  8.            {
  9.                total = total + arr2D[i][j];
  10.                count++;
  11.            }
  12.            
  13.        }
  14.        
  15.        double average = total / count;
  16.        
  17.        return average;
  18.    }

Explanation:

The code in method <em>calcAverage</em> is quite similar to method <em>calcTotal</em>. We just need to add a counter and use that counter as a divisor of total values to obtain an average.

Line 4: Declare a variable, count, as an counter and initialize it to zero.

Line 11: Whenever an element of the 2D array is added to the total, the count is incremented by one. By doing so, we can get the total number of elements that exist in the array.

Line 16: Use the count as a divisor to the total to get average

Line 18: Return the average of all the values in the array as an output.

Answer:

3) calcRowAverage:

  1. public static double calcRowAverage(long [][] arr2D, int row){
  2.        double total = 0;
  3.        int count = 0;
  4.        
  5.        for(int i = 0; i < arr2D.length; i++ )
  6.        {
  7.            if(i == row)
  8.            {
  9.                for(int j = 0; j < arr2D[i].length; j++)
  10.                {
  11.                    total = total + arr2D[i][j];
  12.                    count++;
  13.                }
  14.            }
  15.            
  16.        }
  17.        
  18.        double average = total / count;
  19.        
  20.        return average;
  21.    }

Explanation:

By using method <em>calcAverage </em>as a foundation, add one more parameter, row, in the method <em>calcRowAverage</em>. The row number is used as an conditional checking criteria to ensure only that particular row of elements will be summed up and divided by the counter to get an average of that row.

Line 1: Add one more parameter, row,

Line 8-15: Check if current row index, i, is equal to the target row number, proceed to sum up the array element in that particular row and increment the counter.

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